(a) The magnitude of the acceleration of the electron is 5.62 x 10¹³ m/s².
(b) The speed of the electron after the given time is 4.78 x 10⁵ m/s.
<h3>
Acceleration of the electron</h3>
The acceleration of the electron is calculated as follows;
F = qE
ma = qE
a = qE/m
a = (1.6 x 10⁻¹⁹ x 320)/(9.11 x 10⁻³¹)
a = 5.62 x 10¹³ m/s²
<h3>Speed of the electron</h3>
v = at
v = 5.62 x 10¹³ m/s² x 8.50 x 10⁻⁹ s
v = 4.78 x 10⁵ m/s
Learn more about speed here: brainly.com/question/4931057
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According to Newton's Second Law of Motion :
The Force acting on an Object is equal to Product of Mass of the Object and Acceleration produced due to the Force.
Force acting = Mass of the Object × Acceleration
Given : Force = 50 newton and Mass of the Object = 10 kg
Substituting the respective values in the Formula, we get :
50 N = 10 kg × Acceleration
Acceleration of the Object = 5 m/s²
Along plate edges, at points where oceanic or continental plates meet ot at the edges of the plates
Answer:
ΔT = 0.02412 s
Explanation:
We will simply calculate the time for both the waves to travel through rail distance.
FOR THE TRAVELING THROUGH RAIL:
FOR THE WAVE TRAVELING THROUGH AIR:
The separation in time between two pulses can now be given as follows:
<u>ΔT = 0.02412 s</u>
Potential energy is the store she energy from an object this could include rubber bands. Kinetic energy is the energy that deals with motion a good example is a person running
