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notka56 [123]
3 years ago
12

The part of the atom that carries no electric charge

Physics
1 answer:
AlexFokin [52]3 years ago
7 0
The answer is: A Neutron
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What are the four answers (in order) to fill in these blanks?<br><br> URGENT
ser-zykov [4K]

In a circuit, the electromotive force can be said to be the "source" of the "pushed electrons". This push then creates what is known as a current, which is the flow of electric charge through the circuit. This flow can be slowed down or restricted by a resistor, and this is also what can be harnessed in order to use electric power.

Explanation:

The electromotive force is the potential difference produced by the battery in the circuit. When the circuit is connected to the battery, this potential difference causes the electron to start moving towards the point at higher potential: in this sense, the electromotive force is said to be the "source" of the "pushed electrons".

This flow of electrons moving in the circuit is known as current.

Then, in the circuit, it is possible to place a piece of circuit with a smaller cross-section that restricts the flow of electrons: this component is known as resistor, and its property of restricting the flow of electron is known as resistance.

In a circuit, electromotive force (V), current (I) and resistance (R) are related by Ohm's law:

V=RI

Finally, when a current passes through a resistor, part of the electric energy is converted into thermal energy, and some power is dissipated through the resistor. The power dissipated is given by

P=I^2 R

This power can be harnessed, for instance, if the resistor is connected to a light bulb: the energy is transformed into heat and light, and so the light bulb turns on, providing illumination.

Learn more about current and resistance:

brainly.com/question/4438943

brainly.com/question/10597501

brainly.com/question/12246020

#LearnwithBrainly

3 0
3 years ago
Match the term to the correct description.
stiks02 [169]
1. Resistor
2. Insulator
3. Current
4. Semiconductor
5. Conductor
4 0
3 years ago
To what physical quantity do ampere-hours correspond, and what relationship do ampere-hours have to energy content?
navik [9.2K]

Electric charge

Explanation:

The ampere-hour corresponds to the unit of electric charge.

 Electric charge = electric current x time

    electric current is measured in amperes

     time is measured in hours

The ampere-hour is the current transferring one charge in one hour.

The ampere hour can be used to express the energy require to move a current of 1A in a hour.

The quantity is related to electric charge and the energy in a battery.

Learn more:

Electric circuit brainly.com/question/10421964

#learnwithBrainly

4 0
4 years ago
In an experiment, a research collected the following informationabout a solution made from a certain
velikii [3]

Answer:

salt

Explanation:

6 0
3 years ago
Air with a mass flow rate of 2.3 kg/s enters a horizontal nozzle operating at steady state at 450K, 350kPa, and a velocity of 3
MissTica

Answer:

(a) A_1=0.283m^2

(b) Q=-105.5kW: From the air to the surroundings.

Explanation:

Hello,

(a) In this case, we can compute the area at the entrance by firstly computing the inlet volumetric flow:

V_1=\frac{mRT_1}{P_1M}= \frac{2.3\frac{kg}{s} *8.314\frac{kPa*m^3}{kmol* K}*450K}{350kPa*28.97\frac{kg}{kmol} } =0.849\frac{m^3}{s}

Then, with the velocity, we compute the area:

A_1=\frac{V_1}{v_1}=\frac{0.849\frac{m^3}{s} }{3\frac{m}{s} }  =0.283m^2

(b) In this case, via the following energy balance for the nozzle:

Q-W=H_2-H_1+\frac{1}{2} mV_2^2-\frac{1}{2} mV_1^2

We can easily compute the change in the enthalpy by using the given Cp and neglecting the work (no done work):

\Delta H=H_2-H_1=mCp\Delta T=2.3kg/s*1.011\frac{kJ}{kg*K}*(300K-450K)\\ \\\Delta H=-348.795kW

Finally, the heat turns out:

Q=-348.795kW+\frac{1}{2}*2.3\frac{kg}{s}*[(460\frac{m}{s})^2   -(3\frac{m}{s})^2  ]\\\\Q=-348.795kW+243329.65W*\frac{1kW}{1000W}\\ \\Q=-105.5kW

Such sign, means the heat is being transferred from the air to the surroundings.

Regards.

4 0
3 years ago
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