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2 years ago

2+2=? what does two plus two equal?

Mathematics

2 answers:

BigorU [14]2 years ago

6 0

Answer:

Step-by-step explanation:

Gelneren [198K]2 years ago

4 0

Answer:

Step-by-step explanation:

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Alicia has been putting her money from work into her savings account. The equation f(x)=13x+100 can be used to represent the inc

labwork [276]

Answer:

f(18)=334

Step-by-step explanation:

f(x)=13x+100
f(18) = 13(18)+100
f(18)=234+100
f(18)=334

3 0

2 years ago

What is 0.7, 7/9, 7/8 in order from greatest to least

Sphinxa [80]

Simple...

change them all into fractions or decimals...

0.7---> 0.7

$\frac{7}{9}$ -->>0.77

$\frac{7}{8}$ --->>0.875

Ordering from greatest to least....

0.875-->>0.77-->>0.7

$\frac{7}{8}$ -->> $\frac{7}{9}$ -->>0.7

Thud, your answer.

5 0

2 years ago

9th grade Algebra 1 help??

andriy [413]

3 eggs for brownies, 2 eggs for cookies.

Because the total count went up 2 for one more batch of cookies, you know that 1C(ookies) = 2 eggs
3C = 6 eggs
15 - 6 = 9 eggs
3B(rownies) = 9 eggs
1B = 3 eggs

8 0

2 years ago

PLEASE HELP NOW --- >N is a 2-digit even number. If the last two digits of N^2 is the same as N, what is the sum of digits of

taurus [48]

Answer:

76.

Step-by-step explanation:

It is given that N is a 2-digit number.

Last two digits of N^2 is the same as N.

We know that, a number is even if it ends with 0,2,4,6,8.

$2^2=4,4^2=16,6^2=36,8^2=64$

If 0 is in end then we get two zeros in the square of that number.

It is clear that, number should ends with 6 to get the same number at the end.

$16^2=256$

$26^2=676$

$36^2=1296$

$46^2=2116$

$56^2=3136$

$66^2=4356$

$76^2=5776$

$86^2=7396$

$96^2=9216$

It is clear that last two digits of (76)^2 is the same as 76.

Therefore, the required number is 76.

6 0

3 years ago

Let f (x) = 3x − 1 and ε > 0. Find a δ > 0 such that 0 < ∣x − 5∣ < δ implies ∣f (x) − 14∣ < ε. (Find the largest

s344n2d4d5 [400]

Answer:

This proves that f is continous at x=5.

Step-by-step explanation:

Taking f(x) = 3x-1 and $\varepsilon>0$ , we want to find a $\delta$ such that $|f(x)-14|$

At first, we will assume that this delta exists and we will try to figure out its value.

Suppose that $|x-5|$ . Then

$|f(x)-14| = |3x-1-14| = |3x-15|=|3(x-5)| = 3|x-5|< 3\delta$ .

Then, if $|x-5|$ , then $|f(x)-14|$ . So, in this case, if $3\delta \leq \varepsilon$ we get that $|f(x)-14|$ . The maximum value of delta is $\frac{\varepsilon}{3}$ .

By definition, this procedure proves that $\lim_{x\to 5}f(x) = 14$ . Note that f(5)=14, so this proves that f is continous at x=5.

3 0

2 years ago