The number of mole of H in NH₃, given the data is 23.85 moles
<h3>Data obtained from the question</h3>
- Mole of NH₃ = 7.95 moles
- Mole of H in NH₃ =?
<h3>How to determine the mole of H in 7.95 moles of NH₃</h3>
1 mole of NH₃ contains 3 moles of H
Therefore,
7.95 moles of NH₃ will contain = 7.95 × 3 = 23.85 mole of H
Thus, 23.85 mole of H is present in 7.95 moles of NH₃
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Answer:
I am not sure what was the passage but the relationship between clownfish and sea anemone is mutualism where they both benefit each other.
Answer:
P[H2] = P[I2] = 0.02 atm
P[HI] = 5.98 atm
Explanation:
The ICE table for the given reaction is:
H2(g) + I2(g) ↔ 2HI(g)
Initial 3.01atm 3.01atm -
Change -x -x +2x
Equilib (3.01-x) (3.01-x) 2x
The equilibrium constant, Kp is given as:
x = 2.99 atm
Equilibrium partial pressure of H2 = I2 = 3.01-2.99 = 0.02 atm
Equilibrium partial pressure of HI = 2x = 2(2.99) = 5.98 atm
Answer:
B.
Explanation:
The neutron/proton ratio for a certain element must fall within a certain range for the element to be stable. That’s why some isotopes of an element are stable and others are radioactive.
All of the above are true