A=AB*DE=(8+4)*7=12*7=84 m^2
A=84 m^2
Answer: <em>the length of each edge is 0.5 ft.</em>
Step-by-step explanation:
![V=S^{3}\\\\S=\sqrt[3]{V}=\sqrt[3]{\dfrac{1}{8}} = \sqrt[3]{\bigg ( \dfrac{1}{2} \bigg)^{3} } = \dfrac{1}{2}=0.5 \: \: \: (ft)](https://tex.z-dn.net/?f=V%3DS%5E%7B3%7D%5C%5C%5C%5CS%3D%5Csqrt%5B3%5D%7BV%7D%3D%5Csqrt%5B3%5D%7B%5Cdfrac%7B1%7D%7B8%7D%7D%20%20%3D%20%5Csqrt%5B3%5D%7B%5Cbigg%20%28%20%5Cdfrac%7B1%7D%7B2%7D%20%5Cbigg%29%5E%7B3%7D%20%7D%20%20%3D%20%5Cdfrac%7B1%7D%7B2%7D%3D0.5%20%5C%3A%20%5C%3A%20%5C%3A%20%28ft%29)
Given that,
The area parameters are
A = 2.7 cm, B = 4.1 cm C = 4.5 cm
We want to find the angle extended by B.
Using cosine Rule
b² = a² + c² - 2ac•Cosθ
4.1² = 2.7² + 4.5² - 2 × 2.7 × 4.5• Cosθ
16.81 = 7.29 + 20.25 - 24.3•Cosθ
16.81 - 7.29 - 20.25 = -24.3•Cosθ
-10.73 = -24.3•Cosθ
Cosθ = -10.73 / -24.3
Cosθ = 0.4416
θ = Cos~1 (0.4416)
θ = 63.8°
The angle B is 63.8°
Answer:
15120
Step-by-step explanation:
Given:
The number of players at point guard = 10
The number of players at shooting guard = 12
The number of players at small forward = 7
The number of players at power forward = 2
The number of players at center = 9
Then, the number of different teams William could draft is given by:
10 x 12 x 7 x 2 x 9
William could draft 15120 different teams.
Answer:
8 < x < 2 has no solution because there is no number greater than 8 (8 < x), yet less than 2 (x < 2). It's impossible, so there is no solution.
If the inequality was something like 8 < x < 10, then it will work because 8 can be less than x and x can be less than 10.
Hope this helps and have a great rest of your day! :)
