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slega [8]
2 years ago
5

1. What type of battery was made by alternating layers of silver, zinc and blotting paper soaked in salt?

Chemistry
2 answers:
Sunny_sXe [5.5K]2 years ago
4 0

Answer:

voltaic piles

Explanation:

:3

Allisa [31]2 years ago
4 0

Answer:

Ik someone already answered it correctly, but it is voltaic piles.

Explanation:

You might be interested in
Una muestra de 2,5000 (g) de piedra caliza, se disuelve y se precipita el Calcio como oxalato de Calcio (CaC2O4), este precipita
sergij07 [2.7K]

Answer:

\%Ca=19.378\%

Explanation:

¡Hola!

En este caso, basado en la información dada, es posible conocer la masa de calcio en carbonato de calcio, que de hecho es la misma en la muestra, al utilizar el siguiente esquema de cálculo:

m_{Ca}=1,2093gCaCO_3*\frac{1molCaCO_3}{100.1gCaCO_3}*\frac{1molCa}{1molCaCO_3}*\frac{40.1gCa}{1molCa}\\\\m_{Ca}=0.48444gCa

Finalmente, calculamos el porcentaje requerido como sigue:

\% Ca=\frac{0.48444g}{2.5000g} *100\%\\\\\%Ca=19.378\%

¡Saludos!

4 0
3 years ago
What is the formula for 2-methylnonane
Vera_Pavlovna [14]

Answer:

C10H22

sorry if im wrong

5 0
3 years ago
A piece of metal has a mass of 500 g and a volume of 5 cm3. What is its specific gravity?
Vadim26 [7]
I believe the answer is 100. Hope this helps. (ノ◕ヮ◕)ノ*:・゚✧
density = mass/volume.

3 0
3 years ago
How many acetate ions are formed when three formula units of zinc acetate dissociate?
jeyben [28]
A formula unit is the same as the empirical formula of a compound or an ionic molecule. It is the lowest ratio of the atoms in the compound or ion. Zinc acetate ions dissociates into zinc ions and acetate ions. The dissociation reaction is expressed as follows:
Zn(O2CCH3)2 = Zn2+ + 2(O2CCH3)1-

We determine the amount of acetate ions produced as follows:

Moles Zn(O2CCH3)2 = (3 formula units Zn(O2CCH3)2) ( 1 mol / 6.022x10^23 formula units) = 4.98x10^-24 mol Zn(O2CCH3)2
moles (O2CCH3)1- = 4.98x10^-24 mol Zn(O2CCH3)2 ( 2 mol (O2CCH3)1- / 1 mol Zn(O2CCH3)2 ) = 9.96x10^-24 mol (O2CCH3)1-
# of acetate ions = 9.96x10^-24 mol (O2CCH3)1- ( 6.022x10^23 ions / 1 mol (O2CCH3)1-) = 6 acetate ions
3 0
3 years ago
After standardizing a NaOH solution, you use it to titrate an HCl solution known to have a concentration of 0.203 M. You perform
jek_recluse [69]

Answer:

0.203 is the mean of the concentration of the HCl solution

Explanation:

You have 5 concentrations. The most appropiate result is the mean of those results. The mean is a statistical defined as the sum of each result divided by the total amount of results. For the results of the problem, the mean is:

0.210 + 0.204 + 0.201 + 0.202 + 0.197 = 1.014 / 5 =

<h3>0.203 is the mean of the concentration of the HCl solution</h3>
8 0
2 years ago
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