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olchik [2.2K]
3 years ago
5

Choose the correct one ​

Chemistry
1 answer:
Roman55 [17]3 years ago
5 0

Answer:

B. More reactant is added.

Explanation:

The question basically asks at which condition would the forward reaction be favoured.

The law of equilibrium states when a system at equilibrium is disturbed by, it would annul that change. In order to increase the forward reaction, more of the reactant should be added. In order to annul this change, the system would have to favour the reaction that deals with reducing the amount of reactant added.

The correct option is;

B. More reactant is added.

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Chemical or physical change? and what made you think such?​
spayn [35]

Answer:

it's a chemical change and an electrolytic reaction

8 0
4 years ago
Read 2 more answers
Please help!!!! Thank you
kolezko [41]
The answer is “C“ since the earth rotation makes it seem like the stars and sun is moving when in reality we are moving ฅ^•ﻌ•^ฅ
6 0
3 years ago
The combustion of a sample of butane, C4H10 (lighter fluid), produced 2.46 grams of water.
avanturin [10]

a. 0.137

b. 0.0274

c. 1.5892 g

d. 0.1781

e. 5.6992 g

<h3>Further explanation</h3>

Given

Reaction

2 C4H10 + 13O2 -------> 8CO2 + 10H2O

2.46 g of water

Required

moles and mass

Solution

a. moles of water :

2.46 g : 18 g/mol = 0.137

b. moles of butane :

= 2/10 x mol water

= 2/10 x 0.137

= 0.0274

c. mass of butane :

= 0.0274 x 58 g/mol

= 1.5892 g

d. moles of oxygen :

= 13/2 x mol butane

= 13/2 x 0.0274

= 0.1781

e. mass of oxygen :

= 0.1781 x 32 g/mol

= 5.6992 g

6 0
3 years ago
How many ions of aluminum oxide (Al²O³) are there in 200 g of Al²O³??<br><br>​
valentinak56 [21]

= 6.022 × 1020

Explanation<em>;</em>

Mole of aluminium oxide (Al2O3) is

⇒ 2 x 27 + 3 x 16

Mole of aluminium oxide = 102 g

i.e., 102 g of Al2O3= 6.022 x 1023 molecules of Al2O3

Then, 0.051 g of Al2O3 contains = 6.022 x 1023 / (102 x 0.051 molecules)

= 3.011 x 1020 molecules of Al2O3

The number of aluminium ions (Al3+) present in one molecule of aluminium oxide is 2.

Therefore, the number of aluminium ions (Al3+) present in 3.11 × 1020 molecules (0.051g) of aluminium oxide (Al2O3)

= 2 × 3.011 × 1020

=<em> 6.022 × 1020</em>

<em>hope </em><em>it </em><em>helps</em><em>_</em>

6 0
2 years ago
Please help!!!!!!!!!!!!!!!!!! Now that the lab is complete, it’s time to write your lab report. The purpose of this guide is to
Inessa [10]

Answer:

what was the lab?

Explanation:

8 0
4 years ago
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