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olchik [2.2K]
3 years ago
5

Choose the correct one ​

Chemistry
1 answer:
Roman55 [17]3 years ago
5 0

Answer:

B. More reactant is added.

Explanation:

The question basically asks at which condition would the forward reaction be favoured.

The law of equilibrium states when a system at equilibrium is disturbed by, it would annul that change. In order to increase the forward reaction, more of the reactant should be added. In order to annul this change, the system would have to favour the reaction that deals with reducing the amount of reactant added.

The correct option is;

B. More reactant is added.

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A general term for a chemical which accelerates a reaction without becoming chemically involved is called a ______.
AleksAgata [21]

Answer:

Catalyst

Explanation:

A general term for a chemical which accelerates a reaction without becoming chemically involved is called a catalyst.

Catalysts are used in industrial processes to speed up the rate of a chemical reaction. For instance, in the Contact process used in the production of sulphuric (vi) acid, vanadium(V) oxide (V2O5) is used as a catalyst to speed up the production of the acid. Vanadium(V) oxide (V2O5) is preferred to Platinum which was initially used as the catalyst since it does not react with any of the products of the process

6 0
3 years ago
Given the balanced equation: 2KClO₃ ---> 2KCl + 3O₂ How many moles of O₂ are produced when 4.0 moles of KCl are produced?
Verizon [17]

Answer:

The answer to your question is 6.0 moles of O₂

Explanation:

Data

                      2KClO₃    ⇒     2KCl    +    3O₂

moles of O₂ = ?

moles of KCl = 4

Process

To find the number of moles of O₂, use proportions and cross multiplication.

Use the coefficients of the balanced equation.

                    2 moles of KCl ----------------- 3 moles of O₂

                    4 moles of KCl -----------------  x

                          x = (4 x 3) / 2

-Simplification

                          x = 12/2

-Result

                        x = 6 moles of O₂

-Conclusion

When 4,0 moles of KCl are produced, 6.0 moles of O₂ will be produced.                          

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4 years ago
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Answer:

is this in your text book

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3 years ago
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