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3 years ago

I need help with this please.

Chemistry

1 answer:

Mamont248 [21]3 years ago

4 0

C
E
B
D
F
A
Hope this helps!!

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What are the classes of alkanol

LuckyWell [14K]

1-PRIMARY ALKANOL 2-SECONDARY ALKANOL 3-TERTIARY ALKANOL

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4 years ago

How many half-lives are required for the concentration of reactant to decrease to 1.56% of its original value?4247.56.56

neonofarm [45]

Answer:

6 half-lives are required for the concentration of reactant to decrease to 1.56% of its original value.

Explanation:

Using integrated rate law for first order kinetics as:

$[A_t]=[A_0]e^{-kt}$

Where,

$[A_t]$ is the concentration at time t

$[A_0]$ is the initial concentration

Given:

Concentration is decreased to 1.56 % which means that 0.0156 of $[A_0]$ is decomposed. So,

$\frac {[A_t]}{[A_0]}$ = 0.0156

Thus,

$\frac {[A_t]}{[A_0]}=e^{-k\times t}$

$0.0156=e^{-k\times t}$

kt = 4.1604

The expression for the half life is:-

Half life = 15.0 hours

$t_{1/2}=\frac {ln\ 2}{k}$

Where, k is rate constant

So,

$k=\frac {ln\ 2}{t_{1/2}}$

$\frac{4.1604}{t}=\frac {ln\ 2}{t_{1/2}}$

$t = 6\times t_{1/2}$

<u>6 half-lives are required for the concentration of reactant to decrease to 1.56% of its original value.</u>

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4 years ago

What is amu of 99 % H-1, .2% H-1 and .8% H-3

ankoles [38]

The average atomic mass of your mixture is 1.03 u .

The average atomic mass of H is the weighted average of the atomic masses of its isotopes.

We multiply the atomic mass of each isotope by a number representing its relative importance (i.e., its % abundance).

Thus,

0.99 × 1.01 u = 0.998 u

0.002 × 2.01 u = 0.004 u

0.008 × 3.02 u = <u>0.024 u</u>

TOTAL = 1.03 u

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3 years ago

How many elements are found in the following chemical equation? K + Cl → KCl A. 1 B. 2 C. 3 D. 0

Gnesinka [82]

K is Potassium
Cl is Chlorine
There are 2 elements.

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3 years ago

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Question 2

QveST [7]

Metals only and ionic

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I need help with this please.​

I need help with this please.