Question

Calculate the mass of silver nitrate (in grams) in a 145 mL solution of 5.88 M AgNO3?

Answer 1

Answer: The mass of silver nitrate is 137.5 grams.

Explanation:

Molarity is defined as the number of moles present in one liter of solution.

Mathematically,

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Or,

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Molarity of solution = 5.88 M

Molar mass of silver nitrate = 170 g/mol

Volume of solution = 145 mL

Mass of silver nitrate = ? g

Putting values in above equation, we get:

$5.58mol/L=\frac{\text{Mass of silver nitrate}\times 1000}{170g/mol\times 145mL}\\\\\text{Mass of silver nitrate}=\frac{5.58\times 170\times 145}{1000}=137.5g$

Hence, the mass of silver nitrate is 137.5 grams.

Answer 2

1 mole of AGNO3 weighs 170g
so 0.6322 miles will weigh 170 X 0.6322=107.474 g