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Y_Kistochka [10]
3 years ago
11

Calculate the mass of silver nitrate (in grams) in a 145 mL solution of 5.88 M AgNO3?

Chemistry
2 answers:
Alika [10]3 years ago
7 0

<u>Answer:</u> The mass of silver nitrate is 137.5 grams.

<u>Explanation:</u>

Molarity is defined as the number of moles present in one liter of solution.

Mathematically,

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Or,

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Molarity of solution = 5.88 M

Molar mass of silver nitrate = 170 g/mol

Volume of solution = 145 mL

Mass of silver nitrate = ? g

Putting values in above equation, we get:

5.58mol/L=\frac{\text{Mass of silver nitrate}\times 1000}{170g/mol\times 145mL}\\\\\text{Mass of silver nitrate}=\frac{5.58\times 170\times 145}{1000}=137.5g

Hence, the mass of silver nitrate is 137.5 grams.

oee [108]3 years ago
6 0
1 mole of AGNO3 weighs 170g
so 0.6322 miles will weigh 170 X 0.6322=107.474 g
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