All categories

3 years ago

What chemical compound is crucial to marine life and how is it disappearing?

1 answer:

5 0

Nitrogen is crucial to the marine life and it is disappearing because it cannot be assimilated by most organisms in the water.

You might be interested in

Dry air is primarily made up of nitrogen (78.09%) and oxygen (20.95%). which of these is the solvent and which is the solute?

Vlada [557]

Nitrogen is the Solvent and Oxygen is the Solute.

7 0

3 years ago

Read 2 more answers

Which of the following hydrocarbons has a double bond in its carbon skeleton?1) C3H82) C2H63) CH44) C2H45) C2H2

Kipish [7]

Answer:

C₂H₄ (option number 4)

Explanation:

A hydrocarbon with a double bond in its carbon skeleton is an alkene and has the general form:

$C_nH_{2n}$ .

This is, the number of hydrogen atoms is twice the number of carbon atoms.

On the other hand, alkanes have only single bonds, and the compounds with a triple bond in its carbon skeleton are alkynes.

Review each choice:

1) C₃H₈:

In this case, the number of hydrogen atoms is 2×3 + 2 = 6 + 2 = 8, which is corresponds to an alkane, not an alkene.

2) C₂H₆

For this, the number of hydrogen atoms is 2 × 2 + 2 = 4 + 2 = 6. Again an alkane, not alkene.

3) CH₄

Hydrogen atoms: 1 × 2 + 2 = 4 ⇒ an alkane

4) C₂H₄

Hydrogen atoms: 2 × 2 = 4. This is precisely the relation for an alkene, so this is the hydrocarbon that has a double bond in its carbon skeleton.

The chemical formula may be writen as CH₂ = CH₂, to show the double bond.

So, this is the correct answer.

5) C₂H₂

Hydrogen atoms: 2 × 2 - 2 = 4 - 2 = 2. This relation of carbon and hydrogen atoms corresponds to a compound with triple bond, i.e an alkyne: CH≡CH.

8 0

3 years ago

One mole of an ideal gas, for which CV,m = 3/2R, initially at 298 K and 1.00 × 105 Pa undergoes a reversible adiabatic compressi

oksian1 [2.3K]

Answer:

final temperature (T2) = 748.66 K
ΔU = w = 5620.26 J
ΔH = 9367.047 J
q = 0

Explanation:

ideal gas:

PV = RTn

reversible adiabatic compression:

δU = δq + δw = CvδT

∴ q = 0

∴ w = - PδV

⇒ δU = δw

⇒ CvδT = - PδV

ideal gas:

⇒ PδV + VδP = RδT

⇒ PδV = RδT - VδP = - CvδT

⇒ RδT - RTn/PδP = - CvδT

⇒ (R + Cv,m)∫δT/T = R∫δP/P

⇒ [(R + Cv,m)/R] Ln (T2/T1) = Ln (P2/P1) = Ln (1 E6/1 E5) = 2.303

∴ (R + Cv,m)/R = (R + (3/2)R)/R = 5/2R/R = 2.5

⇒ Ln(T2/T1) = 2.303 / 2.5 = 0.9212

⇒ T2/T1 = 2.512

∴ T1 = 298 K

⇒ T2 = (298 K)×(2.512)

⇒ T2 = 748.66 K

⇒ ΔU = Cv,mΔT

⇒ ΔU = (3/2)R(748.66 - 298)

∴ R = 8.314 J/K.mol

⇒ ΔU = 5620.26 J

⇒ w = 5620.26 J

H = U + nRT

⇒ ΔH = ΔU + nRΔT

⇒ ΔH = 5620.26 J + (1 mol)(8.314 J/K.mol)(450.66 K)

⇒ ΔH = 5620.26 J + 3746.787 J

⇒ ΔH = 9367.047 J

8 0

3 years ago

Are substances that taste bitter and feel slippery to the skin

frez [133]

Answer:

Explanation:

Bases are the substances which have a bitter taste and feel slippery.
Sulfuric acid is the most widely made industrial chemical in the world. It is used to make many products, including paper, paint, detergents, and fertilizers. Car batteries contain sulfuric acid. Feel The properties of a base solution include a bitter taste and a slippery feel.

4 0

3 years ago

The coolant in automobiles is often a 50/50 % by volume mixture of ethylene glycol, C2H6O2, and water. At 20°C, the density of e

Misha Larkins [42]

Explanation:

Let the volume of the solution be 100 ml.

As the volume of glycol = 50 = volume of water

Hence, the number of moles of glycol = $\frac{mass}{molar mass}$