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Setler79 [48]
3 years ago
5

What does a 10-dB increase in loudness represent?

Physics
1 answer:
Naddika [18.5K]3 years ago
6 0
If you smack your hands together, that would be about 10db

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Determine the density of a rectangular piece of concrete that measures 3.7 cm by 2.1 cm by 5.8 cm and has a mass of 43.8 grams.
Novay_Z [31]
It is customary to work in SI units.

Calculate the volume of the concrete.
V = 3.7*2.1*5.8 cm³ = 45.066 cm³ = 45.066 x 10 ⁻⁶ m³

The mass is  43.8 g = 43.8 x 10⁻³ kg

The density is mass/volume.
Density = (43.8 x 10⁻³ kg)/(45.066 x 10⁻⁶ m³) = 971.9 kg/m³

Answer: 971.9 kg/m³
5 0
3 years ago
A 10 kg package is delivered to your house.
kolbaska11 [484]
In ur explanation make sure to use the terms
7 0
2 years ago
During the deceleration of an ascending elevator, the normal force on the feet of a passenger is _____ her weight. During the de
gizmo_the_mogwai [7]

Answer: Smaller than ; larger than

Explanation:

When the elevator is moving in the upward direction, then the force acting on it is negative in nature because of

N= mg +ma, (g is gravity and a is acceleration)

here ma is negative so the N= mg-ma

Hence, it feels smaller than its original weight.

When the elevator is moving downward , then the force acting will be positive in nature

N= mg+ma,

here ma will be positive so it feels larger the original weight of passenger.

7 0
2 years ago
You throw a ball straight down from an apartment balcony to the ground below. The ball has an initial velocity of 5.00m/s, direc
erik [133]
The height of the balcony may be calculated through the equation,
                                h = V₀t + 0.5gt²
where h is the height, V₀ is the initial velocity, g is the gravitational constant and t is time. Substituting the values given above,
                               h = (5 m/s)(2s) + 0.5(10 m/s²)(2 s)²
                                 h  = 30 m
Thus, the height of the balcony is 30 meters. 
5 0
3 years ago
A man is doing push-ups. he has a mass of 68 kg and his center of gravity is located at a horizontal distance of 0.70 m from his
lidiya [134]
Mass m = 68 kg
center of gravity from his palms x = 0.7 m
center of gravity from his feet x ' = 1 m
forces exerted by the floor on his palms and feet are F and F ' respectively.

with respect to palms :---------------------

( F*0 ) - (W * x ) + [ F ' * (x+x') ] = 0

             -mg*0.7 + F ' * 1.7 = 0    where W = weight = mg

F ' * 1.7 = mg * 0.7

          F ' = mg * 0.7 / 1.7

               = 68 *9.8 * ( 0.7 / 1.7 )

               = 274.4 N

with respect to feet :--------------------

( F ' * 0 ) -( W* x ' ) + [F * ( x + x') ] = 0

                -mg*1 + [ F * 1.7 ]= 0

                                 F = mg / 1.7

                                    = 392 N
7 0
3 years ago
Read 2 more answers
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