4 years ago

Theorem: A line parallel to one side of a triangle divides the other two proportionately.

Mathematics

2 answers:

ZanzabumX [31]4 years ago

8 0

<span> Segment BF = 18
just took the test</span>

Svetradugi [14.3K]4 years ago

7 0

In your question which ask for the statement that best fit in your theorem that a parallel line to one side of a triangle divides the other two porportionately which states that segment DE is parallel to segment BC and segment EF is parallel to AB so the answer is BD=15

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The volume of a right rectangular prism is 573.3 cm³. The length of the right rectangular prism is 7.35 cm and the height is 16.

IgorLugansk [536]

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3 0

4 years ago

Use the value of the first integral I to evaluate the two given integrals. I = integral^3_0 (x^3 - 4x)dx = 9/4 A. integral^3_0 (

Troyanec [42]

Answer:

A) -9/2

B) 9/4

C) -9/2, same as A)

Step-by-step explanation:

We are given that $I=\int_0^3 x^3-4x dx=9/4$ . We use the properties of integrals to write the new integrals in terms of I.

A) $\int_0^3 8x-2x^3 dx=\int_0^3 -2(x^3-4x) dx=-2\int_0^3 x^3-4x dx=-2I=-9/2$ . We have used that ∫cf dx=c∫f dx.

B) $\int_3^0 4x - x^3 dx=-\int_0^3 (4x-x^3) dx=\int_0^3-(4x-x^3) dx=\int_0^3 x^3-4x dx=I=9/4$ . Here we used that reversing the limits of integration changes the sign of the integral.