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kvasek [131]
3 years ago
6

Sodium thiosulfate (Na2S2O3), photographer’s

Chemistry
2 answers:
qwelly [4]3 years ago
8 0

Answer:

0.30 moles of sodium thiosulfate formula units are needed to make 0.10 moles of AgBr soluble.

Explanation:

3Na_2S_2O_3+AgBr\rightarrow NaBr+Na_5[Ag(S_2O_3)_3]

According to reaction , 1 mole of silver bromide dissolves in 3 moles of Sodium thiosulfate .

Then 0.10 moles of AgBr will dissolve with:

\frac{3}{1}\times 0.10 mol=0.30 mol

0.30 moles of sodium thiosulfate formula units are needed to make 0.10 moles of AgBr soluble.

vova2212 [387]3 years ago
3 0

3Na2S2O3 + AgBr ------>Na5[Ag(S2O3) 3] +NaBr

from equation 3 mol 1 mol

given x mol 0.10 mol


x= (3*0.10)/1=0.30 mol Na2S2O3


Answer: 0.30 mol Na2S2O3

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