Radon-222 is a radioactive gas with a half-life of 3.82 days. How long would it take for 15/16 of the sample of radon-222 to dec
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Answer:
3.18 mol
Explanation:
n(CO2) = mass/ Mr.
= 25.5 / 16
= 1.59 mol
As per the equation above,
n(LiOH) : n(CO2)
2 : 1
∴ 3.18 : 1.59
Answer : The final volume of gas will be, 103.3 L
Explanation :
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,
where,
= initial pressure of gas = 740.0 mmHg = 98.4 kPa
Conversion used : (1 mmHg = 0.133 kPa)
= final pressure of gas = 99.3 kPa
= initial volume of gas = 106.0 L
= final volume of gas = ?
= initial temperature of gas =
= final temperature of gas =
Now put all the given values in the above equation, we get:
Therefore, the final volume of gas will be, 103.3 L