Sandpaper is a type of rough material that is rubbed on other surfaces to make them smoother. Ms. Fonger is rubbing a piece of s
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Here we have to get the spin of the other electron present in a orbital which already have an electron which has clockwise spin.
The electron will have anti-clockwise notation.
We know from the Pauli exclusion principle, no two electrons in an atom can have all the four quantum numbers i.e. principal quantum number (n), azimuthal quantum number (l), magnetic quantum number (m) and spin quantum number (s) same. The importance of the principle also restrict the possible number of electrons may be present in a particular orbital.
Let assume for an 1s orbital the possible values of four quantum numbers are n = 1, l = 0, m = 0 and s = .
The exclusion principle at once tells us that there may be only two unique sets of these quantum numbers:
1, 0, 0, + and 1, 0, 0, -
.
Thus if one electron in an orbital has clockwise spin the other electron will must be have anti-clockwise spin.
Answer:
The correct option is: e) n=4, l=3, = - 2 ,
= - 1/2
Explanation:
The four quantum numbers that describe the electrons in an atom are: The principal: n, azimuthal: l, magnetic: m, and spin: s.
For a given electron, the values of the quantum numbers should be in the <u>given range</u>- principal quantum number: n ≥ 1;
azimuthal quantum number: 0 ≤ l ≤ n − 1;
magnetic quantum number: −l ≤ ≤ +l;
spin quantum number: −s ≤ ≤ +s
Now, for n= 4,
The value of l: 0 to n − 1 = 0 to 3 = 0, 1, 2, 3
The value of for l= 3 : -3 to +3 = -3, -2, -1, 0, +1, +2, +3
The value of : -1/2, +1/2
<u>Therefore, the given set of quantum numbers</u>: n=4, l=3, = - 2 ,
= - 1/2; <u>are possible and permissible for an electron in an atom.</u>