What is the mass of silver in 3.4g of AgNO3?
1 answer:
3.4g AgNO3 x (1 mole AgNO3/169.8732g AgNO3) x (1 mole Ag/1mole AgNO3) x (107.8682g Ag/1 mole Ag) =
<span>2.2 grams Ag </span>
<span>(2 significant figures </span>
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