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Anni [7]
3 years ago
7

ReAcTanTS and PrOducTS

Chemistry
1 answer:
telo118 [61]3 years ago
5 0

Answer:

START and STOP, ReAcTanTS means START, PrOducTS means STOP

Explanation:

1. We find words 'STOP' and 'START'.

2. Let's take a look at the word 'ReAcTanTS'. Enumerate the capital letters from 1 to 5 from left to right, that is,

'1': R,

'2': A,

'3': T,

'4': T,

'5': S.

Notice that if we take a combination of 54213, we obtain a word 'start'. This has, of course, a chemical application. Reactants are the ones we start with in a chemical reaction.

3. Let's take a look at the word 'PrOducTS'. Enumerate the capital letters from 1 to 4 from left to right, that is:

'1': P,

'2': O,

'3': T,

'4': S.

Notice that if we take a combination of 4321, we obtain a word 'stop'. Similarly to the previous word, it also has a direct relationship to the chemical context. Products are formed in a chemical reaction when reactants combine. This is the point where reaction comes to and end and eventually stops if it's a typical one-sided reaction.

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murzikaleks [220]

H3PO4 has molecular weight of approximately 98 grams per mole. 4.50 M is equal to 4.50 mole per 1000 mL solution of H3PO4. 255 mL times 4.50 mol /1000 mL times 98 g/mol is equal to 112.455 grams. Note that I automatically equate 1 Liter to 1000 mL since the given volume is in mL for easier computation.

7 0
3 years ago
A chemical reaction takes place inside a flask submerged in a water bath. The water bath contains 8.10kg of water at 33.9 degree
lions [1.4K]

Answer:

The new temperature of the water bath 32.0°C.

Explanation:

Mass of water in water bath ,m= 8.10 kg = 8100 g ( 1kg = 1000g)

Initial temperature of the water = T_1=33.9^oC=33.9+273K=306.9 K

Final temperature of the water = T_2

Specific heat capacity of water under these conditions =  c = 4.18 J/gK

Amount of energy lost by water = -Q = -69.0 kJ = -69.0 × 1000 J

( 1kJ=1000 J)

Q=m\times c\times \Delta T=m\times c\times (T_2-T_1)

-69.0\times 1000 J=8100 g\times 4.18 J/g K\times (T_2-306.9 K)

-69,000.0 J=8100 g\times 4.18 J/g K\times (T_2-306.9 K)

T_2=304.86 K=304.86 -273^oC=31.86^oC\approx 32.0^oC

The new temperature of the water bath 32.0°C.

5 0
3 years ago
Question 4 (1 point)
BigorU [14]
The answer to your question is full
6 0
3 years ago
Read 2 more answers
How many grams of FeCo3 will be produced from 57.2g FeCl2
Evgesh-ka [11]

Answer:

             287.30 g of FeCO₃

Solution:

The Balance Chemical Equation is as follow,

                           FeCl₂ + Na₂CO₃    →    FeCO₃ + 2 NaCl

Step 1: Calculate Mass of FeCl₂ as,

                            Molarity  =  Moles ÷ Volume

Solving for Moles,

                            Moles  =  Molarity × Volume

Putting Values,

                            Moles  =  2 mol.L⁻¹ × 1.24 L

                           Moles  =  2.48 mol

Also,

                            Moles  =  Mass ÷ M.Mass

Solving for Mass,

                            Mass  =  Moles × M.Mass

Putting Values,

                            Mass  =  2.48 mol × 126.75 g.mol⁻¹

                            Mass =  314.34 g of FeCl₂

Step 2: Calculate Mass of FeCO₃ formed as,

According to equation,

          126.75 g (1 mole) FeCl₂ produces  =  115.85 g (1 mole) FeCO₃

So,

               314.34 g of FeCl₂ will produce  =  X g of FeCO₃

Solving for X,

                     X =  (314.34 g × 115.85 g) ÷ 126.75 g

                     X =  287.30 g of FeCO₃

<h2>brainlyest pleas</h2>
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4 0
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