1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Anni [7]
3 years ago
7

ReAcTanTS and PrOducTS

Chemistry
1 answer:
telo118 [61]3 years ago
5 0

Answer:

START and STOP, ReAcTanTS means START, PrOducTS means STOP

Explanation:

1. We find words 'STOP' and 'START'.

2. Let's take a look at the word 'ReAcTanTS'. Enumerate the capital letters from 1 to 5 from left to right, that is,

'1': R,

'2': A,

'3': T,

'4': T,

'5': S.

Notice that if we take a combination of 54213, we obtain a word 'start'. This has, of course, a chemical application. Reactants are the ones we start with in a chemical reaction.

3. Let's take a look at the word 'PrOducTS'. Enumerate the capital letters from 1 to 4 from left to right, that is:

'1': P,

'2': O,

'3': T,

'4': S.

Notice that if we take a combination of 4321, we obtain a word 'stop'. Similarly to the previous word, it also has a direct relationship to the chemical context. Products are formed in a chemical reaction when reactants combine. This is the point where reaction comes to and end and eventually stops if it's a typical one-sided reaction.

You might be interested in
For the equilibrium
Mamont248 [21]

Answer:

Equilibrium concentrations of the gases are

H_2S=0.596M

H_2=0.004 M

S_2=0.002 M

Explanation:

We are given that  for the equilibrium

2H_2S\rightleftharpoons 2H_2(g)+S_2(g)

k_c=9.0\times 10^{-8}

Temperature, T=700^{\circ}C

Initial concentration of

H_2S=0.30M

H_2=0.30 M

S_2=0.150 M

We have to find the equilibrium concentration of gases.

After certain time

2x number of moles  of reactant reduced and form product

Concentration of

H_2S=0.30+2x

H_2=0.30-2x

S_2=0.150-x

At equilibrium

Equilibrium constant

K_c=\frac{product}{Reactant}=\frac{[H_2]^2[S_2]}{[H_2S]^2}

Substitute the values

9\times 10^{-8}=\frac{(0.30-2x)^2(0.150-x)}{(0.30+2x)^2}

9\times 10^{-8}=\frac{(0.30-2x)^2(0.150-x)}{(0.30+2x)^2}

9\times 10^{-8}=\frac{(0.30-2x)^2(0.150-x)}{(0.30+2x)^2}

By solving we get

x\approx 0.148

Now, equilibrium concentration  of gases

H_2S=0.30+2(0.148)=0.596M

H_2=0.30-2(0.148)=0.004 M

S_2=0.150-0.148=0.002 M

3 0
3 years ago
How do you solve this ??
kotegsom [21]
Answer : Option A) 2.00 eV

Explanation : The conversion of J to eV is done with the following formula;

E_{eV} = E_{J} X (6.241 X 10^{18})

Here, we have the value of particle in terms of Joules which is 3.2 X 10^{-19}

So, on substituting we get,
E_{eV} = 3.2 X 10^{-19}  X  (6.241 X 10^{18} )


E_{eV} = 1.99 eV so, it can be rounded off to 2.00 eV.
3 0
3 years ago
Which letter pattern best represents seafloor spreading? (Hint: Letter "f" represents the mid-
labwork [276]

Answer:

anna ou

Explanation:

6 0
3 years ago
Read 2 more answers
How many solute particles are found inside the cell
vazorg [7]

it should either be 5 or 10


7 0
3 years ago
What happens to an object's temperature if the kinetic energy of its particles decrease
ser-zykov [4K]
The temperature decreases
8 0
4 years ago
Other questions:
  • What examples does<br> - Making Materials<br> - Moving Materials<br> - Removing Waste
    13·1 answer
  • What is a molarity a measurement
    8·1 answer
  • When wind drops its load of sand,it can form a hill called
    11·1 answer
  • 1.0 L of .50 M of NaCl
    8·1 answer
  • What is the molar mass of Al2(SO4)3
    5·2 answers
  • Help me please!! :D​
    14·1 answer
  • The original list from the Stockholm Convention on Persistent Organic Pollutants (POPs) of 12 hazardous chemicals, called the __
    12·1 answer
  • Which statement best explains why an object appears green in sunlight?
    10·1 answer
  • Give the meaning of each of the following symbols when used in a chemical equation.
    8·1 answer
  • Clo3− draw the molecule by placing atoms on the grid and connecting them with bonds. Include all lone pairs of electrons. Show t
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!