First we need to find the common ratio by dividing the second term by the first term. 36/120 = 3/10
an = a1 * r^(n-1)
n = term to find = 5
a1 = first term = 120
r = common ratio = 3/10
now we sub and solve
a5 = 120 * 3/10^(5 - 1)
a5 = 120 * 3/10^4
a5 = 120 * .0081
a5 = 0.972 <=== fifth term
or we could have just done this......since we multiply by 3/10 to find the next number...
a3 = 10.8......10.8 * 3/10 = 3.24 <== 4th term
3.24 * 3/10 = 0.972 <== fifth term
multiply 40 by 30% to find the discount then subtract
40 * 0.30 = 12
40-12 = 28
they would cost $28
C=2πr=π/2
2πr=π/2
4πr=π
r=π/4π=1/4
A=πr^2=(1/4)^2*π=1/16*π
Answer: 17500
Step-by-step explanation: 7000 + 15000 + 22000 + 23000 +38000/ 6
For this case what you must do is to graph both lines. (See attached graph) and see where both are cut.
We note that both lines are cut at the point (2,5)
Therefore the solution for f (x) = g (x) is x = 2
answer x = 2
