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GenaCL600 [577]
4 years ago
6

Draw the curved arrow mechanism for the addition of HCN in water with NaOH to heptan-4-one to give the corresponding cyanohydrin

in the fewest steps. Draw the arrows that lead to the resonance structures with full octets around each atom other than hydrogen. Draw all electrons and charges if necessary on all structures; do not show any inorganic side products or counterions. Reagents needed for each step are provided in the boxes.

Chemistry
1 answer:
Troyanec [42]4 years ago
3 0

Answer:

Cyanohydrin is formed through nucleophilic addition of cyanide ion to carbonyl center of the given ketone

Explanation:

  • NaOH maintains basic medium. Hence dissociation of HCN gets favored to produce nucleophile CN^{-}
  • In first step, CN^{-} is produced through dissociation of HCN.
  • In second step, CN^{-} gives nucleophilic addition at the cabonyl center of heptan-4-one,
  • In the third step, protonation of negatively charged oxygen atom occurs leading to formation of cyanohydrin.
  • Full reaction mechanism has been shown below.  

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A 100.0 ml sample of 0.18 m hclo4 is titrated with 0.27 m lioh. determine the ph of the solution before the addition of any lioh
snow_lady [41]
Thank you for posting your question here at brainly. Below is the solution:

 <span>moles HClO4 = 0.100 L x 0.18 M = 0.018 
moles LiOH = 0.030 L x 0.27 = 0.0081 
moles H+ in excess = 0.018 - 0.0081 = 0.0099 
total volume = 0.130 L 
[H+] = 0.0099/ 0.130= 0.0762 M 
pH = 1.12</span>
3 0
3 years ago
What mass of H₂ is needed to react with 8.75 g of O₂ according to the following equation: O2(g) + H2(g) → H₂O(g)?
FromTheMoon [43]

Explanation:

For reacting with 8.75 grams of oxygen, 1.08 grams of hydrogen is required.

The given balanced equation has been:

\rm O_2\;+\;2\;H_2\;\rightarrow\;H_2OO2+2H2→H2O

From the equation, 1 mole of oxygen reacts with 2 mole of hydrogen to give 1 mole of water.

The mass of oxygen has been: 8.75 g,

Moles = \rm \dfrac{weight}{molecular\;weight}molecularweightweight

Moles of oxygen = \rm \dfrac{8.75}{32}328.75

Moles of oxygen = 0.27 mol

Since,

1 mole Oxygen = 2 mole hydrogen

0.21 mol oxygen = 0.54 mol hydrogen

Mass of hydrogen = moles \times× molecular weight

Mass of hydrogen = 0.54 \times× 2

Mass of hydrogen = 1.08 grams.

Thus, for reacting with 8.75 grams of oxygen, 1.08 grams of hydrogen is required.

6 0
2 years ago
Oxygen is important in the oxidation of glucose because it ____________________________. Oxygen is important in the oxidation of
Vlad [161]

can be oxidized to form carbon dioxide

Explanation:

Oxygen is important in the oxidation of glucose because it can be oxidized to form carbon dioxide. Oxidation of glucose involves the reaction of oxygen with glucose in a process called respiration. This gives a product of water, carbon dioxide and energy which is stored as ATP.

  • Oxidation involves the addition of oxygen.
  • Any specie that undergoes oxidation, is a reducing agent and it is said to be oxidized.
  • Oxygen is oxidized to form carbon dioxide and water.

Learn more:

Respiration and photosynthesis brainly.com/question/3437832

#learnwithBrainly

3 0
3 years ago
Convert 55.0 miles per hour to feet per second
labwork [276]

Answer:

80.667

Explanation:

math

7 0
2 years ago
Surrounding ions with water molecules is known as
Stells [14]

Answer:

Hydration  

Explanation:

In water, ions are surrounded by a sphere of water molecules called a hydration shell. The process of forming this shell is called hydration.

3 0
3 years ago
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