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klasskru [66]
2 years ago
5

The term gas is limited to those substances that exist in the gaseous state at

Chemistry
1 answer:
Assoli18 [71]2 years ago
3 0
Physical change alters a given material without changing its chemical.
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How is stoichiometry used to calculate the amount of product from amount of reactant?
IceJOKER [234]
<span>Stoichiometry deals with the quantitative measurement of reactants and products in a chemical reaction. Let suppose you are given with following reaction;

                                            A  +  2 B   </span>→    3 C

According to this reaction 1 mole of A reacts with 2 moles of B to produce 3 moles of C. Now using the concept of mole one can easily measure the amount of reactants reacted and the amount of product formed, as...

                    1 Mole Exactly equals 6.022 × 10²³ particles

                    1 Mole of Gas (at STP) exactly occupies 22.4 L Volume

                    1 Mole of any compound exactly equals the molar mass in                                 grams

Therefore, <span>Stoichiometry is very helpful in quantitative analysis.</span>
6 0
2 years ago
Read 2 more answers
There are two isotopes of chlorine. below is a list of each and their mass and abundance. calculate the atomic mass of chlorine.
Vesna [10]
Chlorine is very lequid structure
6 0
3 years ago
The student who answers the riddle will get the prize ? underline pronoun<br>.​
mariarad [96]

answer:

the student <u>who</u> answers the riddle will get the prize

explanation:

  • who is the pronoun
  • a pronoun is something that substitutes for a noun
6 0
2 years ago
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What is difference between layer A and layer b? ​
lakkis [162]

Answer:

can you send me a picture of what layer a and look b look like and then I will be able to evaluate

7 0
2 years ago
Hat volume of a 0.540 M NaOH solution contains 12.5 g NaOH
amid [387]

Answer:

At 0.58 L of 0.540 M NaOH solution contain 12.5 g NaOH.

Explanation:

Given data:

At volume = ?

Mass of NaOH = 12.5 g

Molarity of solution = 0.540 M

Solution:

First of all we will calculate the number of moles of sodium hydroxide.

Number of moles = mass/molar mass

Number of moles = 12.5 g / 40 g/mol

Number of moles = 0.3125 mol

Volume of NaOH:

Molarity = number of moles / volume in L

Now we will put the values.

0.540 M = 0.3125 mol / volume in L

volume in L = 0.3125 mol / 0.540 mol/L

volume in L = 0.58 L

5 0
3 years ago
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