According to the balanced equation of this reaction:
N2(g) + 3H2(g) ↔ 2NH3(g)
and when we have Kp = 4.51 x 10^-5 so, in the Kp equation we will substitute by the value of the P for each gas to compare the value with Kp = 4.51x10^-5
a) when we have 98 atm NH3, 45 atm N2, 55 atm H2 by substitution in Kp equation:
Kp= [p(NH3)]^2 / [p(N2)]*[p(H2)]^3 = [98]^2 / [45]*[55]^3
= 1.28x10^-3
So here the value is higher than the value of the given Kp.
so the reaction will go leftwards toward the reactants ( to reduce the value of Kp) to reach the equilibrium.
b) When 57 atm NH3, 143 atm N2, No H2 so like a) by substitution:
Kp = [57]^2 / [143] = 22.7
So the reaction will go leftwards toward the reactants to reduce the value of Kp to reach equilibrium.
c) when 13 atm NH3, 27 atm N2, 82 H2
Kp = [13]^2 / [27]*[82]^3 = 1.135 x 10^-5 So this value is lower than the Kp which is given.
so, the reaction will go towards the right toward the products to increase the value of Kp to reach the equilibrium.
Answer:
290.32 g
Explanation:
First we <u>calculate the volume</u> of the cube:
- Volume = (3.20 cm)³ = 32.768 cm³
Now we <u>convert cubic centimeters to mililiters</u>:
- 32.768 cm³ * 1 mL / 1 cm³ = 32.768 mL
Finally we <u>calculate the mass</u>, using the <em>equation for density</em>:
- mass = 8.86 g/mL * 32.768 mL = 290.32 g
Answer:
0.022 M
Explanation:
The molarity is the number of mol solute divided by the volume of solution in liters. Since we are told there is only one acidic hydrogen in KHP the reaction is a 1 to 1 with sodium hydroxide, We then calculate the moles of sodium hydroxide required to react with the moles of KHP and proceed to calculate the molarity of the NaOH solution:
mol KHP: 0.1082 g x 1 mol/204.22 g = 0.00053 mol KHP
0.00053 mol KHP x 1 mol Naoh/1 mol KHP = 0.00053 mol NaOH
Molarity of the solution : 0.00053 mol NaOH / 0.02346 L = 0.022 M
note: The volume of sodium hydroxide needed to be converted to liters by definition of molarity.
Answer:
you can tell diorite is an intrusive igneous rock because it has a coarse-grained texture
