Answer:
mass of a particular object remains the same where ever it is placed, the mass will remain the same whether the object is on the moon or earth, unlike weight which will change.
Weight is affected by gravity. Therefore it is dependent on gravity or directly proportional to the force of gravity.
weight = mass × gravity
The gravity on earth is much larger than the gravity on the moon. Therefore the weight of an object weighs heavier on earth than on the moon. The object when placed on the moon will have a lower weight.
The difference is that the weight of the object on the moon will be lower than the weight of the object on earth.
The similarity is that the mass of an object will remain the same, regardless if it's placed on the moon or earth.
Hope this helps.
It would be velocity over frequency look up equation
Answer:
The expected ratio of half-lives for a reaction will be 5:1.
Explanation:
Integrated rate law for zero order kinetics is given as:
![k=\frac{1}{t}([A_o]-[A])](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B1%7D%7Bt%7D%28%5BA_o%5D-%5BA%5D%29)
![[A_o]](https://tex.z-dn.net/?f=%5BA_o%5D)
= initial concentration
[A]=concentration at time t
k = rate constant
if, ![[A]=\frac{1}{2}[A_o]](https://tex.z-dn.net/?f=%5BA%5D%3D%5Cfrac%7B1%7D%7B2%7D%5BA_o%5D)
, the equation (1) becomes:
![t_{\frac{1}{2}}=\frac{[A_o]}{2k}](https://tex.z-dn.net/?f=t_%7B%5Cfrac%7B1%7D%7B2%7D%7D%3D%5Cfrac%7B%5BA_o%5D%7D%7B2k%7D)
Half life when concentration was 0.05 M=
Half life when concentration was 0.01 M=
Ratio of half-lives will be:
![\frac{t_{\frac{1}{2}}}{t_{\frac{1}{2}}'}=\frac{\frac{[0.05 M]}{2k}}{\frac{[0.01 M]}{2k}}=\frac{5}{1}](https://tex.z-dn.net/?f=%5Cfrac%7Bt_%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D%7Bt_%7B%5Cfrac%7B1%7D%7B2%7D%7D%27%7D%3D%5Cfrac%7B%5Cfrac%7B%5B0.05%20M%5D%7D%7B2k%7D%7D%7B%5Cfrac%7B%5B0.01%20M%5D%7D%7B2k%7D%7D%3D%5Cfrac%7B5%7D%7B1%7D)
The expected ratio of half-lives for a reaction will be 5:1.
