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3 years ago

Which of the following is a reduction half-reaction?

1 answer:

3 0

Solution : An oxidation reduction (redox) reaction is a type of chemical reaction that involves a transfer of electrons between tow species an oxidaion reductin reaction is any chemical reaction in which the oxidation number of a molecule atom or ion changes by gaining or losing an electron

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Covalent solutes are considered non-electrolytes. What does this mean for the conductivity of the solution? A) Non-electrolytes

iogann1982 [59]

Electrolytes are those which dissociates in solution and produces ions.

Ions can carry current,so Electrolytes conduct electiricity.

And non electrolytes are those which do not dissociate in solution and doesnt produce ions.

Since non electrolytes do not produce ions they cannot conduct electricity.

Hence the right option is:

B) Non-electrolytes dissolve and do not dissociate in water providing no charged ions to conduct electricity.

5 0

2 years ago

Read 2 more answers

Calculate the standard enthalpy of formation of NOCl(g) at 25 ºC, knowing that the standard enthalpy of formation of NO(g) at th

stepan [7]

Answer:

The standard enthalpy of formation of NOCl(g) at 25 ºC is 105 kJ/mol

Explanation:

The ∆H (heat of reaction) of the combustion reaction is the heat that accompanies the entire reaction. For its calculation you must make the total sum of all the heats of the products and of the reagents affected by their stoichiometric coefficient (number of molecules of each compound that participates in the reaction) and finally subtract them:

Enthalpy of the reaction= ΔH = ∑Hproducts - ∑Hreactants

In this case, you have: 2 NOCl(g) → 2 NO(g) + Cl₂(g)

So, ΔH= $2*H_{NO} +H_{Cl_{2} }-2*H_{NOCl}$

Knowing:

ΔH= 75.5 kJ/mol
$H_{NO}$ = 90.25 kJ/mol
$H_{Cl_{2} }$ = 0 (For the formation of one mole of a pure element the heat of formation is 0, in this caseyou have as a pure compound the chlorine Cl₂)
$H_{NOCl}$ =?

Replacing:

75.5 kJ/mol=2* 90.25 kJ/mol + 0 - $H_{NOCl}$

Solving

- $H_{NOCl}$ =75.5 kJ/mol - 2*90.25 kJ/mol

- $H_{NOCl}$ =-105 kJ/mol

$H_{NOCl}$ =105 kJ/mol

The standard enthalpy of formation of NOCl(g) at 25 ºC is 105 kJ/mol

8 0

3 years ago

Identify the species oxidized. 2 al3+(aq) + 2 fe(s) → 2 al(s) + 3 fe2+(aq)

Sliva [168]

To know the answer, compare the oxidation number of the element in the reactant and the product side. The oxidation number of Al was originally +3, then became 0 after the reaction. On the other hand, Fe was originally 0, then became +2 after the reaction. When the element is oxidized, it oxidation number increases. Thus, the element oxidized is Fe.

8 0

3 years ago

Why does temperature change always move from regions of hot to regions of cold?

Nadya [2.5K]

Answer:

earth surface is uneven because land heats faster than water causes air to warm.,expand and rise over land while it cools and sinks over the cooler waters surface..

8 0

3 years ago

What volume of 3.00 M HCl will form a solution with an acidic pH when mixed with 100 mL of 3.00 M NaOH

Maksim231197 [3]

Answer: The volume of acid should be less than 100 mL for a solution to have acidic pH

Explanation:

To calculate the volume of acid needed to neutralize, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is HCl

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH

We are given:

$n_1=1\\M_1=3.00M\\V_1=?mL\\n_2=1\\M_2=3.00M\\V_2=100mL$

Putting values in above equation, we get:

$1\times 3.00\times V_1=1\times 3.00\times 100\\\\V_1=\frac{1\times 3.00\times 100}{1\times 3.00}=100mL$

For a solution to be acidic in nature, the pH should be less than the volume of acid needed to neutralize.

Hence, the volume of acid should be less than 100 mL for a solution to have acidic pH

7 0

3 years ago