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Harlamova29_29 [7]
3 years ago
14

Order from least to greatest: The square root of 64, 8.8, 26/3, 8 2/7

Mathematics
2 answers:
Dafna1 [17]3 years ago
5 0

8, 8 2/7, 26/3, 8.8

(You have to change 8 2/7 to 8.28 and 26/3 to 8.66

elena-14-01-66 [18.8K]3 years ago
3 0

First get these all in the same form (I'm going to decimals):

√64=8

8.8=8.8

26/3=8.66

8 2/7=8.28

Then its super easy to get it into the order:√64, 8 2/7, 26/3, 26/3

You might be interested in
Simplify by dividing (-3/8) -5/9
Elodia [21]

Answer:

\frac{-27}{40}

Step-by-step explanation:

(\frac{-3}{8})÷\frac{5}{9}

\frac{-3}{8}×\frac{9}{5}

\frac{-27}{40}

6 0
3 years ago
John, Joe, and James go fishing. At the end of the day, John comes to collect his third of the fish. However, there is one too m
Dmitry [639]

Answer:

The minimum possible initial amount of fish:52

Step-by-step explanation:

Let's start by saying that

x = is the initial number of fishes

John:

When John arrives:

  • he throws away one fish from the bunch

x-1

  • divides the remaining fish into three.

\dfrac{x-1}{3} + \dfrac{x-1}{3} + \dfrac{x-1}{3}

  • takes a third for himself.

\dfrac{x-1}{3} + \dfrac{x-1}{3}

the remaining fish are expressed by the above expression. Let's call it John

\text{John}=\dfrac{x-1}{3} + \dfrac{x-1}{3}

and simplify it!

\text{John}=\dfrac{2x}{3} - \dfrac{2}{3}

When Joe arrives:

  • he throws away one fish from the remaining bunch

\text{John} -1

  • divides the remaining fish into three

\dfrac{\text{John} -1}{3} + \dfrac{\text{John} -1}{3} + \dfrac{\text{John} -1}{3}

  • takes a third for himself.

\dfrac{\text{John} -1}{3}+ \dfrac{\text{John} -1}{3}

the remaining fish are expressed by the above expression. Let's call it Joe

\text{Joe}=\dfrac{\text{John} -1}{3}+ \dfrac{\text{John} -1}{3}

and simiplify it

\text{Joe}=\dfrac{2}{3}(\text{John}-1)

since we've already expressed John in terms of x, we express the above expression in terms of x as well.

\text{Joe}=\dfrac{2}{3}\left(\dfrac{2x}{3} - \dfrac{2}{3}-1\right)

\text{Joe}=\dfrac{4x}{9} - \dfrac{10}{9}

When James arrives:

We're gonna do this one quickly, since its the same process all over again

\text{James}=\dfrac{\text{Joe} -1}{3}+ \dfrac{\text{Joe} -1}{3}

\text{James}=\dfrac{2}{3}\left(\dfrac{4x}{9} - \dfrac{10}{9}-1\right)

\text{James}=\dfrac{8x}{27} - \dfrac{38}{27}

This is the last remaining pile of fish.

We know that no fish was divided, so the remaining number cannot be a decimal number. <u>We also know that this last pile was a multiple of 3 before a third was taken away by James</u>.

Whatever the last remaining pile was (let's say n), a third is taken away by James. the remaining bunch would be \frac{n}{3}+\frac{n}{3}

hence we've expressed the last pile in terms of n as well.  Since the above 'James' equation and this 'n' equation represent the same thing, we can equate them:

\dfrac{n}{3}+\dfrac{n}{3}=\dfrac{8x}{27} - \dfrac{38}{27}

\dfrac{2n}{3}=\dfrac{8x}{27} - \dfrac{38}{27}

L.H.S must be a Whole Number value and this can be found through trial and error. (Just check at which value of n does 2n/3 give a non-decimal value) (We've also established from before that n is a multiple a of 3, so only use values that are in the table of 3, e.g 3,6,9,12,..

at n = 21, we'll see that 2n/3 is a whole number = 14. (and since this is the value of n to give a whole number answer of 2n/3 we can safely say this is the least possible amount remaining in the pile)

14=\dfrac{8x}{27} - \dfrac{38}{27}

by solving this equation we'll have the value of x, which as we established at the start is the number of initial amount of fish!

14=\dfrac{8x}{27} - \dfrac{38}{27}

x=52

This is minimum possible amount of fish before John threw out the first fish

8 0
3 years ago
A farmer finds that if she plants 85 trees per acre, each tree will yield 80 bushels of fruit. She estimates that for each addit
vova2212 [387]

Answer:

52 Trees

Step-by-step explanation:

If she plants 85 trees per acre, each tree will yield 80 bushels of fruit.

Yield = 85 X 80

Let x be the additional tree planted per acre.

For each additional tree planted per acre, the yield of each tree will decrease by 4 bushels.

Therefore, the yield:

F(x)=(85+x)(80-4x)\\F(x)=6800-260x-4x^2

Next, we maximize F(x) by taking its derivatives and solving for its critical point.

F'(x)=-260-8x\\$Setting $F'(x)=0,$ we have:$\\-260-8x=0\\8x=-260\\$Divide both sides by 8$\\x=-32.5

F''(x)=-8, $therefore we have a maximum

It is apparent that she currently has too many trees per acre. To get a maximum harvest, she needs to reduce the number of trees by approximately 32.5 trees.

Therefore, number of trees per acre she should plant:

85+(-32.5)

=85-32.5

=52.5 Trees

Since the number of trees can only be an integer and it cannot be greater than 52.5, the number of trees to be planted per acre to maximize her harvest is 52.

5 0
3 years ago
If the sales-tax rate is 7.5%, what is the sales tax on a $48.00 purchase?
madam [21]

The tax is 3.60, the total is 51.60


8 0
3 years ago
Read 2 more answers
Identify the transformation that maps the figure onto itself.
PolarNik [594]
B)
Rotate 360 clockwise about (-4,-3) and reflect across the line x = -4
7 0
3 years ago
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