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Ira Lisetskai [31]
3 years ago
11

Which of the following reactions occurs at the anode in a voltaic cell? Cu2+ (aq) + 2e– → Cu (s)

Mathematics
2 answers:
AleksAgata [21]3 years ago
7 0
Mg (s) -->Mg2+2e-
i know cause i took the test and got it wrong and that's what  it showed as the right answer lol
emmasim [6.3K]3 years ago
7 0

Answer : The correct option is, (3) Mg(s)\rightarrow Mg^{2+}(aq)+2e^-

Explanation :

Voltaic cell : It is a device which is used for conversion of the chemical energy produces in a redox reaction into the electrical energy.

Voltaic cell is also known as the galvanic cell or electrochemical cell.

In the voltaic cell, the oxidation occurs at an anode which is a negative electrode and the reduction occurs at the cathode which is a positive electrode.

From the given reactions,

Mg(s)\rightarrow Mg^{2+}(aq)+2e^- in this reaction, oxidation reaction takes place in which the oxidation of magnesium changes from (0) to (2+). This reaction reaction occurs at anode in voltaic cell.

While in the other reactions,

Cu^{2+}(aq)+2e^-\rightarrow Cu(s) and K^{+}(aq)+1e^-\rightarrow K(s) in both the reactions, the reduction reaction takes place.

And,

Cd^{2+}+Zn\rightarrow Zn^{2+}+Cd this reaction shows both oxidation and reduction reaction.

Hence, the correct option is, (3) Mg(s)\rightarrow Mg^{2+}(aq)+2e^-

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Answer:

<em>0 $20 bills and 10 $5 bills</em>

<em>1 $20 bills and 6 $5 bills</em>

<em>2 $20 bills and 2 $5 bills</em>

Step-by-step explanation:

<u>Equations</u>

Let's set:

x=number of $5 bills

y=number of $20 bills

The total amount Sara has is given by

5x+20y

And we know it's equal to $50, thus:

5x+20y=50

Dividing by 5

x+4y=10

We would need another condition to solve for x and y, but we can determine some combinations that solve the problem.

Solving for x:

x=10-4y

Since both x and y are integers and cannot be negative:

10-4y≥0

Swapping sides:

4y≤10

Dividing by 4:

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Thus, y can only have the values {0,1,2}

For y=0

x=10-4*0=10

x=10

For y=1

x=10-4*1=6

x=6

For y=2

x=10-4*2=2

x=2

Thus, the possible combinations are:

0 $20 bills and 10 $5 bills

1 $20 bills and 6 $5 bills

2 $20 bills and 2 $5 bills

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