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Ira Lisetskai [31]
3 years ago
11

Which of the following reactions occurs at the anode in a voltaic cell? Cu2+ (aq) + 2e– → Cu (s)

Mathematics
2 answers:
AleksAgata [21]3 years ago
7 0
Mg (s) -->Mg2+2e-
i know cause i took the test and got it wrong and that's what  it showed as the right answer lol
emmasim [6.3K]3 years ago
7 0

Answer : The correct option is, (3) Mg(s)\rightarrow Mg^{2+}(aq)+2e^-

Explanation :

Voltaic cell : It is a device which is used for conversion of the chemical energy produces in a redox reaction into the electrical energy.

Voltaic cell is also known as the galvanic cell or electrochemical cell.

In the voltaic cell, the oxidation occurs at an anode which is a negative electrode and the reduction occurs at the cathode which is a positive electrode.

From the given reactions,

Mg(s)\rightarrow Mg^{2+}(aq)+2e^- in this reaction, oxidation reaction takes place in which the oxidation of magnesium changes from (0) to (2+). This reaction reaction occurs at anode in voltaic cell.

While in the other reactions,

Cu^{2+}(aq)+2e^-\rightarrow Cu(s) and K^{+}(aq)+1e^-\rightarrow K(s) in both the reactions, the reduction reaction takes place.

And,

Cd^{2+}+Zn\rightarrow Zn^{2+}+Cd this reaction shows both oxidation and reduction reaction.

Hence, the correct option is, (3) Mg(s)\rightarrow Mg^{2+}(aq)+2e^-

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NutritionCalc Plus uses the equations from the National Academy of Medicine to calculate the Estimated Energy Requirement (EER)
olga nikolaevna [1]

Answer:

The correct option is (A).

Step-by-step explanation:

The equation for the Estimated Energy Requirement (EER) of 19 or more years older men is:

EER = 662 - (9.53 \times AGE) + PA \times (15.91 \times WT + 539 \times HT)

Here,

AGE = age counted in years

PA = appropriate physical activity factor

WT = weight in kilograms

HT = height in meters

The physical activity factor for men and women is:

Activity Level       PA (men)      PA (Women)

Sedentary              1.00                1.00

    Low                    1.11                1.12

  Active                   1.25                1.27

Very Active              1.48                1.45

Given:

AGE = 22 year-old male college student

PA = low = 1.11

WT = 180 pounds = 81.6466 kg

HT = 5'10" = 1.778 m

Compute the value of EER as follows:

EER = 662 - (9.53 \times AGE) + PA \times (15.91 \times WT + 539 \times HT)

        = 662 - (9.53 \times 22) + 1.11 \times (15.91 \times 81.6466 + 539 \times 1.778)\\\\=662-209.66+1.11\times (1298.997406+958.342)\\\\=452.34+2505.64674066\\\\=2957.98674066\\\\\approx 2962

Thus, the EER for a 22-year-old male college student is approximately 2962 kcal.

The correct option is (A).

6 0
3 years ago
2 (3x + 6) = 3 (x - 10)
Masteriza [31]

Answer:

x= -14

Step-by-step explanation:

4 0
3 years ago
Which set is an example of like fractions?
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Answer:

like fractions have the same denominator. So A is correct

7 0
2 years ago
PLEASE HELP ME FAST. WILL MARK AS BRAINLIEST IF GIVEN GOOD ANSWER
Sholpan [36]

Slope is the change in Y over the change in. X

Using two of the given points:

Slope = 70-45 / 25-10

Slope= 25/ 15

Slope = 5/3

6 0
3 years ago
A larger number is double the sum of 3 and a smaller number. The larger number is 2 less than 3 times the smaller number. If y r
Ratling [72]
Y > x
y = 2(3+x)
y = 3x-2
------------------------------
2(3+x) = 3x-2
2(3+x) - (3x-2) = 0
6 + 2x -3x + 2 = 0
8 -x = 0
x = 8
---------------------------
y = 2(3+x) = 2(3+8) = 22
y = 3x-2 = 3*8 -2 = 22
----------------------------------
x = 8 ; y = 22


7 0
3 years ago
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