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Lena [83]
3 years ago
15

Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one sam

e-day ticket is
$35
. For one performance,
40
advance tickets and
30
same-day tickets were sold. The total amount paid for the tickets was
$1250
. What was the price of each kind of ticket?
Mathematics
2 answers:
icang [17]3 years ago
8 0
Advance=x

Same.day=y

x+y=35 so x=35-y

40x+30y=1250

40(35-y)+30y=1250

-10y=-150

y=15

x+15=35

x=20

Cost for Advance ticket: $20
Cost for Same-day ticket: $15



Neporo4naja [7]3 years ago
6 0
Let's set up variables and equations for things that we know from the question, with a standing for advance tickets, and s standing for same day tickets. 

40a + 30s = 1250 
a + s = 35

Let's solve it through substitution. Isolate either variable, a or s. I'll choose to isolate a. Subtract s from both sides.

a = -s + 35

Plug the new knowledge into the first equation, since we now know the value of a

40(-s +35) + 30s = 1250.

Distribute the 40 to the -s and 35

-40s + 1400 + 30s = 1250

Combine the negative and positive s

-10s + 1400 = 1250

Subtract 1400 from both sides.

-10s = -150

Divide both sides by -10

s = 15

The total price of an advanced ticket and same-day ticket is 35, and we know the value of a same-day ticket, so the price of an advance ticket must be 20. 

The final answers are:
advanced ticket = 20
same day ticket = 15


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Answer:

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Step-by-step explanation:

Line AB passes through points A(−6, 6) and B(12, 3). If the equation of the line is written in slope-intercept form, y=mx+b, then m=m equals negative StartFraction 1 Over 6 EndFraction.. What is the value of b?

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3 years ago
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Answer:

Yes, we reject the auto maker's claim.

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