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3 years ago

I need help with this question please

Mathematics

1 answer:

kumpel [21]3 years ago

7 0

x and 4x are supplementary to each other, meaning they add up to 180. So your equation is 180=5x. Divide both sides by 5 to get 36=x.

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A chef uses 12 pounds of butter each day. About how many grams of butter does the chef use each day? Use the conversion factors

Westkost [7]

Answer:

The chef uses 5452.8 grams of butter each day.

Step-by-step explanation:

Given:

Chef use 12 pounds of butter each day.

To find the amount of butter in grams used by chef each day.

Conversion units:

1 pound = 16 ounces

1 ounce = 28.4 grams

Solution:

We need to convert 12 pounds of butter in grams of butter.

We will apply unitary method to carry out the conversion.

If 1 pound = 16 ounces

Then, 12 pounds = $12\ pounds\times\frac{16\ ounces}{1\ pound}= 192\ ounces$

If 1 ounce = 28.4 grams

Then, 192 ounces = $192\ ounces \times \frac{28.4\ grams}{1\ ounce} = 5452.8\ grams$

Thus, the chef uses 5452.8 grams of butter each day.

3 0

3 years ago

1+3 what is 1 plus 3

Tems11 [23]

Answer:78.

I am just correct my guy

4 0

3 years ago

Which set of ordered pairs represents a function?

Butoxors [25]

B is the correct answer.

8 0

3 years ago

Read 2 more answers

You intend to estimate a population proportion with a confidence interval. The data suggests that the normal distribution is a r

SIZIF [17.4K]

Answer:

The critical value that corresponds to a confidence level of 99% is, 2.58.

Step-by-step explanation:

Consider a random variable X that follows a Binomial distribution with parameters, sample size n and probability of success p.

It is provided that the distribution of proportion of random variable X, $\hat p$ , can be approximated by the Normal distribution.

The mean of the distribution of proportion is, $\mu_{\hat p}=\hat p$

The standard deviation of the distribution of proportion is, $\sigma_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}$ .

Then the confidence interval for the population proportion p is:

$CI=\hat p\pm z_{\alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n} }$

The confidence level is 99%.

The significance level is:

$\alpha =1-\frac{Confidence\ level}{100}=1-\frac{99}{100}=1-0.99=0.01$

Compute the critical value as follows:

$z_{\alpha /2}=z_{0.01/2}=z_{0.005}$

That is:

$P(Z>z)=0.005\\P(Z$

Use the z-table for the z-value.

For z = 2.58 the P (Z < z) = 0.995.

And for z = -2.58 the P (Z > z) = 0.005.

Thus, the critical value is, 2.58.

7 0

4 years ago

Al, Pablo, and Marsha shared the driving on a 1,500-mile trip. Which of the three drove the greatest distance on the trip?(1) Al

Svetach [21]

Answer:

Pablo drove the greatest distance of 527 miles.

Missing Content:

Since information on Pablo is not given, it is impossible to solve this problem. Let us assume some scenario for Pablo. Say:

(3)Pablo averaged 52.7 miles per hour and drove for 10 hours.

Step-by-step explanation:

Using this information, we can find out the data on Al,

Al drove 1 hour longer than Pablo so,

Time Al drove= 10+1 =11 hours

Average rate of Al=Pablo's average rate-5= 52.7-5 = 47.7 miles per hour.

We know that,

Average Speed = $\frac{Distance}{Time}$

Distance =Average Speed x Time

Distance travelled by Al = 47.7 x 11 =524.7 miles

Distance Travelled by Marsha = 50 x 9=450 miles

Distance Travelled by Pablo= 52.7 x 10= 527 miles

As we can see that Pablo drove the greatest distance which is 527 miles.

6 0

3 years ago