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Talja [164]
3 years ago
14

Read: https://kids.britannica.com/kids/article/DNA/390730 (Links to an external site.)

Chemistry
1 answer:
kompoz [17]3 years ago
4 0

Answer:

im not doing your whole homework. but ill give you  one cent ;>, whats ur paypal

Explanation:

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A 250. ML sample of 0.3M HCl is partially neutralized by the addition of 100. ML of 0.25M NaOH.Find the concentration of hydroch
GuDViN [60]

Answer:- 0.143 M

Solution:- HCl and NaOH reacts in 1:1 mol ratio as shown in the below reaction:

HCl(aq)+NaOH(aq)\rightleftharpoons NaCl(aq)+H_2O(l)

Let's calculate the initial moles of HCl and the moles of NaOH added to it:

250.mL(\frac{1L}{1000mL})(\frac{0.3molHCl}{1L})

= 0.075 mol HCl

100.mL(\frac{1L}{1000mL})(\frac{0.25molNaOH}{1L})

= 0.025 mol NaOH

Since they react in 1:1 mol ratio, 0.025 mol of NaOH will react with 0.025 moles of HCl.

Remaining moles of HCl = 0.075 - 0.025 = 0.050

Total volume of the solution = 0.250 L + 0.100 L = 0.350 L

So, the concentration of HCl in the resulting solution = \frac{0.050mol}{0.350L}

= 0.143 M

Hence, the concentration of HCl acid in the resulting solution is 0.143 M.

5 0
4 years ago
4.2g of cerium reacted with oxygen to form 5.16g of an oxide of cerium. Find
olganol [36]

Answer:

CeO₂

Explanation:

Hello!

In this case, since we are given the mass of both cerium and the cerium oxide, we can first compute the moles of cerium and the moles of oxygen as shown below:

n_{Ce}=4.2gCe*\frac{1molCe}{140.12gCe}=0.03molCe\\

m_O=5.16g-4.2g=0.96gO\\\\n_O=0.96g*\frac{1molO}{16.0gO} =0.06molO

Now, we simply divide each moles by 0.03 as the fewest moles in the formula to obtain the simplest formula (empirical formula) of this oxide:

Ce=\frac{0.03}{0.03}=1\\\\O =\frac{0.06}{0.03}=2

Thus, the formula turns out:

CeO_2

Regards!

6 0
3 years ago
The scientific method is one application of critical thinking.true or false
kumpel [21]
The best answer between the two choices would be the first option TRUE because the scientific method is used to do more advance research and investigation on things.
3 0
4 years ago
Read 2 more answers
When the equation below is balanced, the coefficient of sulfuric acid, h2so4 is: nacn + h2so4 → na2so4 + hcn?
horsena [70]
<span>2NaCN + (1)H2SO4 → Na2SO4 + 2HCN

</span><span>The coefficient of sulfuric acid is 1.</span>
3 0
3 years ago
What is the density of lead (in g/cm^3 3 ) if a rectangular bar measuring 0.500 cm in height, 1.55 cm in width, and 25.00 cm in
Viktor [21]

Answer:

Density = 11.4 g/cm³

Explanation:

Given data:

Density of lead = ?

Height of lead bar = 0.500 cm

Width of lead bar = 1.55 cm

Length of lead bar = 25.00 cm

Mass of lead bar = 220.9 g

Solution:

Density = mass/ volume

Volume of bar = length × width × height

Volume of bar = 25.00 cm × 1.55 cm × 0.500 cm

Volume of bar = 19.4 cm³

Density of bar:

Density = 220.9 g/ 19.4 cm³

Density = 11.4 g/cm³

3 0
3 years ago
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