Ocean life is changing due to This is happening because This is causing because

You would be most likely to use a slicing machine if you were using the __________ method to produce cookies.

Verizon [17]

You would be most likely to use a slicing machine if you were using the icebox method to produce cookies.

In the icebox method a type of cookie in which the dough is made, rolled into a stick, and refrigerated until the dough hardens. The dough can be removed from the refrigerator, cut into individual pieces, and then baked. The rest of the dough is returned to the refrigerator until needed.

Icebox method, also known as refrigerator cookies, are sliced and baked cookies. The dough is formed into logs, chilled in the refrigerator (also called an icebox), sliced , and then baked.

Learn more about the Icebox method here,

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7 0

2 years ago

A 1.00 g sample of octane (C8H18) is burned in a bomb calorimeter with a heat capacity of 837J∘C that holds 1200. g of water at

lubasha [3.4K]

Answer:

The heat of combustion for 1.00 mol of octane is -5485.7 kJ/mol

Explanation:

Step 1: Data given

Mass of octane = 1.00 grams

Heat capacity of calorimeter = 837 J/°C

Mass of water = 1200 grams

Temperature of water = 25.0°C

Final temperature : 33.2 °C

Step 2: Calculate heat absorbed by the calorimeter

q = c*ΔT

⇒ with c = the heat capacity of the calorimeter = 837 J/°C

⇒ with ΔT = The change of temperature = T2 - T1 = 33.2 - 25.0 : 8.2 °C

q = 837 * 8.2 = 6863.4 J

Step 3: Calculate heat absorbed by the water

q = m*c*ΔT

⇒ m = the mass of the water = 1200 grams

⇒ c = the specific heat of water = 4.184 J/g°C

⇒ ΔT = The change in temperature = T2 - T1 = 33.2 - 25 = 8.2 °C

q = 1200 * 4.184 * 8.2 = 41170.56 J

Step 4: Calculate the total heat

qcalorimeter + qwater = 6863.4 + 41170. 56 = 48033.96 J = 48 kJ

Since this is an exothermic reaction, there is heat released. q is positive but ΔH is negative.

Step 5: Calculate moles of octane

Moles octane = 1.00 gram / 114.23 g/mol

Moles octane = 0.00875 moles

Step 6: Calculate heat combustion for 1.00 mol of octane

ΔH = -48 kJ / 0.00875 moles

ΔH = -5485.7 kJ/mol

The heat of combustion for 1.00 mol of octane is -5485.7 kJ/mol

8 0

3 years ago

Calculate the mass of 0.750 mol of the following substance. Na3PO4.

Nookie1986 [14]

Na3 = 23*3 = 69
P = 31
O4 = 16*4 =64
69+ 31+ 64 = 164g/mol
0.75mol = 0.75 * 164 = 123 g

4 0

3 years ago

What happens when the pressure of a gas is decreased?

Serggg [28]

Answer:

The combined gas law states that the pressure of a gas is inversely related to the volume and directly related to the temperature. If temperature is held constant, the equation is reduced to Boyle's law. Therefore, if you decrease the pressure of a fixed amount of gas, its volume will increase.

Explanation:

3 0

3 years ago

PLEASE ANSWERRRRRRRRR

ira [324]

Answer:

C. how the size of a magnet affects the strength of its magnetic pull on objects.

Explanation:

"Magnetic force" is inversely proportional to distance squared. This is also related to the size of a magnet. The bigger the size, the bigger the domain it occupies and the stronger the magnetic field. However, this is not often the case and it largely depends on the types of magnets.

In the situation above, Jazelle wanted to determine how her five different-sized magnet affect the strength of their magnetic pull on the paper clips. In order to do this, she tried to measure the distance. The closer the distance, the higher the magnetic field and the stronger the strength. The farther the distance, the lower the magnetic field and the weaker the strength.

So, this explains the answer.

3 0

3 years ago

Ocean life is changing due toThis is happening becauseThis is causingbecause​

Ocean life is changing due toThis is happening becauseThis is causingbecause