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Fiesta28 [93]
3 years ago
7

The average atomic mass recorded on the periodic table for krypton is 83.80 u. This indicates that the most abundant isotope of

krypton is (2 points) krypton-82 krypton-83 krypton-84 krypton-85
Chemistry
1 answer:
Trava [24]3 years ago
7 0
Krypton-84 is the most abundant type of Krypton. The answer is C.

 If you need this to be explained, I  will do my best it's a bit difficult to say how to find it out, but I will if you need me to.
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What color of light is transmitted and refracted by a prism first?
nevsk [136]

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The red light is refracted least. The violet light is refracted most.

Explanation:

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3 years ago
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Bases in solution produce what type of ions?
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Bases produce hydroxide ions, while acids produce hydrogen ions. 

Bases have a pH of above 7, and are bitter and slippery. 

Answer: <span>c. hydroxide ions</span>
4 0
3 years ago
I just need help plz!
Nesterboy [21]

Answer:

<u>Graphene</u> is a nanomaterial that is often used with other compounds to desalinate and decontaminate water.

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4 0
2 years ago
. In a titration, a 25.0 mL sample of 0.150 M HCl is neutralized with 44.45 mL of Ba(OH)2. a. Write the balanced molecular equat
choli [55]

Answer:

Equation of reaction:

a) 2HCl + Ba(OH)2 ==> CaCl2 + 2H2O

b) Molarity of base = 0.042 M.

Explanation:

Using titration equation

CAVA/CBVB = NA/NB

Where NA is the number of mole of acid = 2

NB is the number of mole of base = 1

CA is the molarity of acid =0.15M

CB is the molarity of base = to be calculated

VA is the volume of acid = 25 ml

VB is the volume of base = 44.45mL

Substituting

0.15×25/CB×44.45 = 2/1

Therefore CB =0.15×25×1/44.45×2

CB = 0.042 M.

5 0
3 years ago
2NO (g) + O2 (g) →2NO2 (g) At equilibrium [NO] = 2.4 × 10 -3 M, [O2] = 1.4 × 10 -4 M, and [NO2] = 0.95 M.
azamat

Answer:

K=1.12x10^9

Explanation:

Hello there!

Unfortunately, the question is not given in the question; however, it is possible for us to compute the equilibrium constant as the problem is providing the concentrations at equilibrium. Thus, we first set up the equilibrium expression as products/reactants:

K=\frac{[NO_2]^2}{[NO]^2[O_2]}

Then, we plug in the concentrations at equilibrium to obtain the equilibrium constant as follows:

K=\frac{(0.95)^2}{(0.0024)^2(0.00014)}\\\\K=1.12x10^9

In addition, we can infer this is a reaction that predominantly tends to the product (NO2) as K>>>>1.

Best regards!

4 0
3 years ago
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