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3 years ago

Which of the following pair of elements could not react to form an ionic compound

Chemistry

1 answer:

goldenfox [79]3 years ago

7 0

Answer:

c and o

Explanation:

Carbon and Oxygen cannot react to form an ionic compound because the two elements are non-metals.

To form an ionic bond, a metal combines with a non-metal through electrostatic attraction of oppositely charged ions.
This leads the bond formation.
Carbon is a non-metal, with oxygen, they will prefer to form a covalent bond where they share their electrons

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gavmur [86]

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3 years ago

Current is applied to a molten mixture of AgF , FeCl2 , and AlBr3 . What is produced at each electrode? STRATEGY Rank the cation

ratelena [41]

Answer:

Cathode: Ag

Anode: Br₂

Explanation:

In the cathode must occur a reduction, so it's more likely to a metal atom be in the cathode. For the metals given the reduction reactions and the potential of reduction are:

Ag⁺ + e⁻ ⇒ Ag⁰ E° = + 0.80 V

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Al⁺³ + 3e⁻ ⇒ Al⁰ E° = -1.66 V

As the potential for Ag is the higher, the reduction will occur for it first, so in the cathode will produce Ag.

For the anode an oxidation must occurs, so the reactions for the nonmetals are:

F₂ + 2e⁻ ⇒ 2F⁻ E° = +2.87 V

Cl₂ + 2e⁻ ⇒ 2Cl⁻ E° = +1.36 V

Br₂ + 2e⁻ ⇒ 2Br⁻ E° = +1.07 V

For oxidation, the less the E°, the faster the reaction will occur, so Br₂ will be formed in the anode.

5 0

3 years ago

How many moles of C2H6 in 3.754 x 1023 molecules of C2H6?

ira [324]

Answer:

n=N/NA

n= 3.754×10²³/6.02×10²³

n= 6.24 s

Explanation

since there is number of molecules, make use of Avogadro's constant to get number of moles.

5 0

2 years ago

Ethane, C2H6, burns in oxygen. First write a balanced equation for this combustion reaction. What mass of oxygen, in grams, is r

iren [92.7K]

Answer:

We need 50.6 grams of oxygen

Explanation:

Step 1: Data given

Mass of ethane = 13.6 grams

Molar mass of ethane = 30.07 g/mol

Step 2: The balanced equation

2C2H6 + 7O2 → 4CO2 + 6H2O

Step 3: Calculate moles ethane

Moles ethane = mass ethane / molar mass ethane

Moles ethane = 13.6 grams / 30.07 g/mol

Moles ethane = 0.452 moles

Step 4: Calculate moles oxygen

For 2 moles ethane we need 7 moles O2 to produce 4 moles CO2 and 6 moles H2O

For 0.452 moles ethane we need 3.5*0.452 = 1.582 moles O2

Step 5: Calculate mass O2

Mass O2 = moles O2 * molar mass O2

Mass O2 = 1.582 moles * 32.0 g/mol

Mass O2 = 50.6 grams

We need 50.6 grams of oxygen

7 0

3 years ago