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3 years ago

ASAP PLEASE HELP FAST Question 3 from the video on Box Plots? *

Mathematics

1 answer:

ludmilkaskok [199]3 years ago

5 0

Answer:

B. would be the answer to your question.

Step-by-step explanation:

median: 25

Range: 28 - 21 = 7

(IQR) interquartile range: 26 - 23 = 3

~hope this helps~

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How to solve the problem

mestny [16]

Substitute 4 for x.
-|4-7|+3
-3+3
f(4) = 0

6 0

3 years ago

I like risking my points for hard homework

ELEN [110]

Answer:

The triangle and the square have the same area because they both have four squares

Step-by-step explanation:

The square has four that are easily shown but the triangle has one full one but when two are split together like some of them when you put the two together they equal one whole.

Have a wonderful day/night/afternoon

7 0

2 years ago

Read 2 more answers

A rectangular plot measures 20 ft. By 30ft. A 3ft wide side walk surrounds it. Find the area of the side walk

r-ruslan [8.4K]

Answer:

336 feet²

Step-by-step explanation:

If we have a rectangle that is 30 by 20 feet, that means the area of that rectangle would be 20 × 30 feet squared, which is 600 ft².

If there is a 3 feet sidewalk surrounding it, that means that the end of the sidewalk will extend 3 feet extra around each side of plot. Since there are two ends to one side, that means an extra six feet is added on to each dimension. Therefore, 36 × 26 are the dimensions of the sidewalk+plot. 36 × 26 = 936 ft².

To find the area of the sidewalk itself, we subtract 600 ft² from 936 ft². This gets us with 336 ft².

Hope this helped!

3 0

2 years ago

Como resuelvo ese problema ?

prisoha [69]

160.
Brainiest please

5 0

3 years ago

Slices of pizza for a certain brand of pizza have a mass that is approximately normally distributed with a mean of 67.7 grams an

Alexxx [7]

Answer:

a. s.e. = 0.338

b. The probability of finding a random slice of pizza with a mass of less than 67.2 grams is 0.5871 or 58.71%

c. The probability of finding a 20 random slices of pizza with a mean mass of less than 67.2 grams is 0.0694 or 6.94%

d. The sample mean of 62.75 would represent the 15th percentile

Step-by-step explanation:

1. Let's review the information provided to us to answer the question properly:

μ of the mass of slices of pizza for a certain brand = 67.7 grams

σ of the mass of slices of pizza for a certain brand = 2.28 grams

2. For samples of size 20 pizza slices, what is the standard deviation for the sampling distribution of the sample mean?

Let's recall that the standard deviation of the sampling distribution of the mean is called the standard error of the mean and its formula is:

μσs.e.= √σ/n, where n is the sample size.

s.e. = √2.28/20

s.e. = 0.338

3. What is the probability of finding a random slice of pizza with a mass of less than 67.2 grams?

Let's find the z-score for X = 67.2, this way:

z-score = (X - μ)/σ

z-score = (67.2 - 67.7)/2.28

z-score = 0.5/2.28

z-score = 0.22 (rounding to the next hundredth)

Now, using the z-table, let's find p, the probability:

p (z = 0.22) = 0.5871

The probability of finding a random slice of pizza with a mass of less than 67.2 grams is 58.71%

4. What is the probability of finding a 20 random slices of pizza with a mean mass of less than 67.2 grams?

Let's use the central limit theorem to find the z-score, this way:

z-score = X - μ/s.e

z-score = 67.2 - 67.7/0.338

z-score = -0.5/0.338

z-score = - 1.48

Now, using the z-table, let's find p, the probability:

p (z = -1.48) = 0.0694

5. What sample mean (for a sample of size 20) would represent the bottom 15% (the 15th percentile)?

For p = 0.150, let's find the z-score:

z-score = - 2.17

z-score = X - μ/s.e

- 2.17 = (X - 67.7)/2.28

- 4.95 = X - 67.7

X = 67.7 - 4.95

X = 62.75 (rounding to the next hundredth)

The sample mean of 62.75 would represent the 15th percentile

7 0

3 years ago