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3 years ago

Common factors of 20,25,40

1 answer:

7 0

The factors of 20 are:
1, 2, 4, 5, 10, 20

The factors of 25 are:
1, 5, 25

The factors of 40 are:
1, 2, 4, 5, 8, 10, 20, 40

The common factors are:
1, 5

The Greatest Common Factor:
GCF = 5

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What are the real zeros y=(x+3)^3+10?

igomit [66]

There is only 1
(x + 3)^3 + 10 = 0
(x + 3)^3 = - 10
(x + 3) = cuberoot(-10)
x = -3 + cuberoot(-10)

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3 years ago

For trapezoid JKLM, A and B are midpoints of the legs. Find AB.

romanna [79]

Answer:

Step-by-step explanation:

The length of the median of a trapezoid equals one-half the sum of the lengths of the bases.

$\begin{array}{rcl}AB & = & \frac{1}{2}(JK + LM)\\\\& = & \frac{1}{2}(19 + 39)\\\\& = & \frac{1}{2}\times 58\\\\& = & \mathbf{29}\\\end{array}$

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4 years ago

Identify the corresponding parts. Angle P corresponds to angle . Angle C corresponds to angle . Angle K corresponds to angle .

Fynjy0 [20]

Answer:

F,Z,F

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

The band at charles high school had a concert for charity. They raised $15,000. Adult tickets were $5 each and student tickets w

Vika [28.1K]

Answer:

Adults =1500 and student= 2500

Step-by-step explanation:

Step one:

GIven data

let Adults be x and student be y in numbers

5x+3y=15000------------1

x+y=4000---------------------2

from 1

x=4000-y, put this in 2, we have

5(4000-y)+3y=15000

20000-5y+3y=15000

-2y=15000-20000

-2y= -5000

2y=5000

divide both sides by 2

y= 2500

put y= 2500 in 2

x+2500= 4000

x= 4000-2500

x=1500

3 0

3 years ago

Please help math question 40 pts

boyakko [2]

I think what you would do is add 2x to the other side so you have 2x+3 is greater than or equal to 5. Subtract 3 and then divide by 2 and you are left with x is greater than or equal to 1

4 0

3 years ago

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