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Rashid [163]
3 years ago
7

[PLEASE ANSWER BOTH QUESTIONS] The following data points represent the number of quesadillas each person at Toby's Tacos ate. So

rt the data from least to greatest. Find the interquartile range (IQR) of the data set.

Mathematics
2 answers:
Fynjy0 [20]3 years ago
5 0

Answer:

Part 1: Already solved.

Part 2: 1 quesadilla.

Step-by-step explanation:

Part 1: The data points given are 0, 0, 1/4, 1/2, 1/2, 1, 1, 1, 5/4, 2, and 2.

The data are already sorted from least to greatest.

Part 2: To get the interquartile range, we must know the first and third quartiles. To find those, we need to know the median of the data.

There are 11 data points, so we can cross out 5 numbers on the left and cross out 5 numbers on the right. That leaves a median of 1.

Since we know the median is 1, we can find the first quartile by finding the median of the following numbers: 0, 0, 1/4, 1/2, 1/2 (any number less than 1). There are five numbers, so cross out two numbers from the left and cross out two numbers from the right. We are left with a first quartile of 1/4.

Now that we have the first quartile, we need to find the third quartile. Since the median was actually the first "1" in the data set, the third quartile will be the median of the numbers to the right of that "1": 1, 1, 5/4, 2, 2. Cross out the leftmost two numbers, and cross out the rightmost two numbers. We are left with a third quartile of 5/4.

Now that we have both the third and first quartiles, we can find the interquartile range! The IQR is calculated by finding the third quartile minus the first quartile. 5/4 - 1/4 = 4/4 = 1.

So, your interquartile range is 1 quesadilla.

Hope this helps!

natta225 [31]3 years ago
5 0

Answer:

1 is already solved :)

1 quesadilla

Step-by-step explanation:

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Step-by-step explanation:

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Los 75 postulantes que fueron aceptados tuvieron notas desde 16 hasta a 20. Si el grupo se hubiera desempeñado de modo homogéneo
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Answer:

Tenemos 75 postulantes, y sus notas están en el rango desde 16 hasta 20.

1) si el grupo es homogéneo y todos tienen la misma nota, entonces todos van a tener la nota media en el rango (16, 20)

Para encontrar esta nota calculamos la suma entre ambos extremos y lo dividimos por 2.

Media = (16 + 20)/2 = 36/2 = 18

La nota sería 18.

2) entre 16 y 20 tenemos:

16, 17, 18, 19 y 20

tenemos 5 notas distintas, entonces si agrupamos a los estudiantes por nota, tendríamos 5 grupos.

3) En una distribución normal, el grupo mas grande debería coincidir con la media del intervalo. Ya sabemos que la media es 18, entonces es esperable que la nota del grupo mas grande sea 18.

4) Si los estudiantes se ordenan en fila según notas tendríamos:

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7x = 35 \\  \frac{7x}{7 }  =  \frac{35}{7}  \\ x = 5

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Simplify<br><br> sqrt(3 + 2 sqrt 2) ...?
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sqrt(2) is \sqrt{2}
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Now, let's simplify \sqrt{3 +2 \sqrt{2} }.
We will use square of sum: (a + b)² = a² + 2ab + b²

\sqrt{3 +2 \sqrt{2} } = \sqrt{1+2+2 \sqrt{2} }= \sqrt{1+2 \sqrt{2}+2 }= \\ &#10;= \sqrt{1^{2} +2*1* \sqrt{2} + (\sqrt{2} ) ^{2} } = \sqrt{(1+ \sqrt{2}) ^{2}} =1+ \sqrt{2}
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Read 2 more answers
Criterion: Identify IV, DV, and hypotheses and evaluate the null hypothesis for an independent samples t test. Data: Use the inf
Papessa [141]

The table is missing in the question. The table is provided here :

Group 1        Group 2

 34.86            64.14      mean

 21.99            20.46      standard deviation

  7                    7                n

Solution :

a). The IV or independent variable = Group 1

    The DV or the dependent variable = Group 2

b).

  $H_0: \mu_1 = \mu_2$

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  Therefore,   $t = \frac{\bar x_1 - \bar x_2}{\sqrt{\frac{s_1^2}{n_1}+\frac{S_2^2}{n_2}}}$

$t = \frac{34.86 - 64.14}{\sqrt{\frac{21.99^2}{7}+\frac{20.46^2}{7}}}$

t = -2.579143

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           df = 7 - 1

               = 6

Therefore the value of p :

  $=T.DIST(-2.579143,6,TRUE)$

 = 0.020908803

The p value is 0.0209

$p< 0.05$

So we reject the null hypothesis and conclude that $\mu_1 < \mu_2$

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