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iVinArrow [24]
3 years ago
9

What is the least common denominator of 5/9 and 1/3

Mathematics
1 answer:
julsineya [31]3 years ago
4 0
The answer is 1/3 because if you calculate it 1/3 is a lower decimal
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The length of a rectangle is 3 more than 3 times its width. The perimeter of the rectangle is 174 inches. What is the length of
saveliy_v [14]

Answer:

<em>l = w + 3cm</em>

<em>l = w + 3cmp = 2l + 2w = 58cm</em>

<em>l = w + 3cmp = 2l + 2w = 58cm </em>

<em>l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:</em>

<em>l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58</em>

<em>l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58</em>

<em>l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58⇒ 4w = 52 ⇒ w = 13</em>

<em>l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58⇒ 4w = 52 ⇒ w = 13 </em>

<em>l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58⇒ 4w = 52 ⇒ w = 13 Plug back in:</em>

<em>l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58⇒ 4w = 52 ⇒ w = 13 Plug back in:l = (13cm) + 3cm = 16cm</em>

<em>l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58⇒ 4w = 52 ⇒ w = 13 Plug back in:l = (13cm) + 3cm = 16cmStep-by-step explanation:</em>

I hope this helps you.

5 0
3 years ago
The numbers -12, -7, -2, 3 follow a pattern. What are the next three numbers in this pattern?
Bas_tet [7]

Answer:

8,13

Step-by-step explanation:

The pattern in +5 so 3+5=8, and 8+5=13

6 0
3 years ago
Read 2 more answers
What is the distance between the points (38, 30) and (14, 20)
Brums [2.3K]
Here's a formula to slove ur problem
√(x₁-x₂) +(y₁-y₂)
=√(38-14) +(30-20)
=√24+10
=√34
6 0
3 years ago
Read 2 more answers
Find the total amount due on a simple-interest loan if the principal is $3000 with a rate of 5% for 10 years.
Korolek [52]
\bf \qquad \textit{Simple Interest Earned Amount}\\\\&#10;A=P(1+rt)\qquad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\\&#10;P=\textit{original amount deposited}\to& \$3000\\&#10;r=rate\to 5\%\to \frac{5}{100}\to &0.05\\&#10;t=years\to &10&#10;\end{cases}&#10;\\\\\\&#10;A=3000(1+0.05\cdot 10)\implies A=3000(1.5)
3 0
3 years ago
PLEASE, I AM DESPERATE! CAN ANYONE, HELP ME WITH MY MATH!
Andru [333]
(6,1)&(5,4)
(7,-3)&(4,-8)
(-8,0)&(1,5)
Basically, you are to find the line that passes through 2 points.
Equation: y2-y1=m(x2-x1)
• x1: 6, x2: 5, y1: 1, y2: 4
(4-1)/(5-6)=m
m=3/-1
m=-3
Hence, m= -3x10^0

• x1: 7, x2: 4, y1: -3, y2: -8
(-8--3)/(4-7)=m
m=(-8+3)/-3
m=-5/-3
m=5/3
m=1.66666667
Hence, m=1.6667x10^0

• x1: -8, x2: 1, y1: 0, y2: 5
(5-0)/(1--8)=m
m=5/(1+8)
m=5/9
m=0.55555556
Hence, m=5.56x10^-1

Hope this helps!



5 0
3 years ago
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