Answers:
el pelo rizado en los perros domina sobre el pelo liso. una pareja de pelo rizado tuvo un cachorro de pelo tambien rizado y del que se quiere saber si es heterocigótico ¿ con que tipo de hembras tendrá que cruzarse?
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El cachorro puede ser "Aa" o "AA". Se quiere saber si es "Aa". Para eso, tendría que cruzarse o con un homocigoto recesivo (aa), puesto que es el que da un 50% de probabilidades de que los hijos sean de pelo rizado.
Entonces, si se cruza con un homocigoto recesivo, la probabilidad de la descendencia debería ser 2 cachorros de pelo rizado y 2 cachorros de pelo liso.
La hembra tendría que ser de pelo liso para asegurarse de que sea homocigoto recesivo.
Si todos los cachorros salen con el pelo rizado, entonces el padre es homocigoto "AA".
Si al menos uno sale con el pelo liso, entonces el padre es heterocigoto "Aa"
2NH3 is equivalent to N2 + H6 since the 2 at the beginning gets distributed to both atoms. Knowing this you can rewite the equation as
H2 + N2 = H6 + N2
The N2 can cancel out leaving
H2 = H6
You now have to ask ‘2 times what equals 6?’ The answer is obviously 3 at this point.
Answer: C. 3
No because if your body has never experienced it before it will not no what to do and most likely the body will just send out/produce the other common antibodies or cells
Answer:
a. all purple flowers in the F1 generation.
Explanation:
According to the given information, the allele for purple flower color (lets assume P) is dominant over while the allele of flower color (p). When two pure breeding purple (PP) and white flowered (pp) plants are crossed, the F1 would have all "purple flowered progeny with genotype Pp".
According to the Mendel's law of dominance, the hybrid genotype exhibits the dominant phenotype. Here, the allele "P" is dominant over allele "p". Hence, the genotype "Pp" would exhibit purple flower color and all the F1 progeny would have purple flowers.
Answer:B antvenin as is always specific
Explanation:othe like antigen are for antibodies snake venom is just venom while penicillin is from fung
