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stira [4]
3 years ago
7

Car A uses tires for which the coefficient of static friction is 0.384 on a particular unbanked curve. The maximum speed at whic

h the car can negotiate this curve is 16.7 m/s. Car B uses tires for which the coefficient of static friction is 0.809 on the same curve. What is the maximum speed at which car B can negotiate the curve
Physics
1 answer:
erica [24]3 years ago
8 0
Car C would like a summary too
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The correct answer is the Golden Gate Bridge
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3 years ago
The exit nozzle in a jet engine receives air at 1200 K, 150 kPa with negligible kinetic energy. The exit pressure is 80 kPa, and
nikitadnepr [17]

Complete question:

The exit nozzle in a jet engine receives air at 1200 K, 150 kPa with negligible kinetic energy. The exit pressure is 80 kPa, and the process is reversible and adiabatic. Use constant specific heat at 300 K to find the exit velocity.

Answer:

The exit velocity is 629.41 m/s

Explanation:

Given;

initial temperature, T₁ = 1200K

initial pressure, P₁ = 150 kPa

final pressure, P₂ = 80 kPa

specific heat at 300 K, Cp = 1004 J/kgK

k = 1.4

Calculate final temperature;

T_2 = T_1(\frac{P_2}{P_1})^{\frac{k-1 }{k}

k = 1.4

T_2 = T_1(\frac{P_2}{P_1})^{\frac{k-1 }{k}}\\\\T_2 = 1200(\frac{80}{150})^{\frac{1.4-1 }{1.4}}\\\\T_2 = 1002.714K

Work done is given as;

W = \frac{1}{2} *m*(v_i^2 - v_e^2)

inlet velocity is negligible;

v_e = \sqrt{\frac{2W}{m} } = \sqrt{2*C_p(T_1-T_2)} \\\\v_e = \sqrt{2*1004(1200-1002.714)}\\\\v_e = \sqrt{396150.288} \\\\v_e = 629.41  \ m/s

Therefore, the exit velocity is 629.41 m/s

6 0
3 years ago
A wire of a given material has an electric field of 0.100 mV/m when a potential is applied. The wire has 8.49 x 1028 conduction
Bond [772]

The uniform current density in the wire is 5.43 x 10²⁷ A/m².

<h3>Current density in the wire</h3>

The uniform current density in the wire is calculated as follows;

J = total current / total area

The given parameters:

  • Conduction of the wire = 8.49 x 10²⁸ e/m²
  • time, t = 2.5 x 10⁻¹⁴ s

J = \frac{I}{A} = \frac{Q}{At} \\\\J = \frac{8.49 \times 10^{28}e/m^3 \ \times \ 1.6 \times 10^{-19} \ C/e}{2.5 \times 10^{-14} \ s \ \times ( 0.1 \times 10^{-3} \ V/m)} \\\\J = 5.43 \times 10^{27} \ A/m^2

Learn more about current density here: brainly.com/question/15266434

#SPJ1

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2 years ago
When astronauts are on spacewalks outside of the International Space Station, they must use a communication system with radio wa
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Light waves are electromagnetic waves while sound waves are mechanical waves. Light waves are transverse while sound waves are longitudinal. Light waves can travel in vacuum. Sound waves require a material medium to travel, and hence, cannot travel in vacuum.

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We all know who was the first man that landed on moon? But were the first words ever heard in space?

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Which describes one event that causes an eclipse?
seraphim [82]

Answer:

earth's shadow covering the moon,thats lunar eclipse

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