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alexira [117]
3 years ago
7

Which of the following describes the reactants of a chemical reaction

Physics
1 answer:
AlekseyPX3 years ago
7 0

The options attached to the question are given below:

A. The substances that are formed.

B.  The substances that are changed.  

C. The starting materials.

D.  The chemical ingredients

ANSWER

The correct option is C.

A chemical reaction is made up of two distinct parts, which are reactants and products. The reactants refers to the starting material of the chemical process, which react together under suitable conditions. The products on the other hand refers to the new substance that is formed as a result of the reaction of the reactants. The reactants are usually find at the left side of chemical equations while the product is found at the right.

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A 1.15-kg mass oscillates according to the equation where x is in meters and in seconds. Determine (a) the amplitude, (b) the fr
ANEK [815]

The complete question is;

A 1.15-kg mass oscillates according to the equation x = 0.650 cos(8.40t) where x is in meters and t in seconds. Determine (a) the amplitude, (b) the frequency, (c) the total energy, and (d) the kinetic energy and potential energy when x = 0.360 m.

Answer:

A) Amplitude; A = 0.650 m

B) Frequency; f = 1.337 Hz

C) total energy = 17.142 J

D) Kinetic energy = 11.884 J

Potential Energy = 5.258 J

Explanation:

We are given;

Mass;m = 1.15 kg

Equation; x = 0.650 cos (8.40t)

(a) The standard form of a wave function is in the form y(x,t) = Asin(kx−ωt+ϕ)

So, comparing terms in our equation in the question to this, the amplitude is;

A = 0.650 m

(b) we know that formula for frequency is;

f = ω/2π

Again, comparing terms in the standard equation and our question, we can see that ω = 8.4

Thus;

f = 8.4/(2π)

f = 1.337 Hz

(c) Formula for the total energy is given by;

E = m•ω²•A²/2

Plugging in the relevant values, we have;

E = (1.15)(8.40)²(0.650)²/2

E = 17.142 J

(d) we want to find the kinetic energy and potential energy when x = 0.360 m.

The formula for kinetic energy in this case is given by;

K = (1/2)•m•ω²•(A² - x²)  

Thus;

K = (1/2) × (1.15) × (8.40)² × ((0.650)² - (0.360)²)

K = 11.884 J

Also, the formula for the potential energy in this case is given by;

U = (1/2)•m•ω²•x²              

Thus;

U = (1/2) × (1.15) × (8.40)² × (0.360)²

U = 5.258 J

3 0
2 years ago
Which part of the atom is not found in the nucleus
DiKsa [7]
The electrons are not found in the nucleus. Electrons are in constant movement in the electron cloud. The only sub-atomic particles in the nucleus are the protons and neutrons.
7 0
2 years ago
A rocket is launched straight up from the earth's surface at a speed of 1.80×104 m/s .part awhat is its speed when it is very fa
balandron [24]
We can solve the problem by using the law of conservation of energy.

When the rocket starts its motion from the Earth surface, its mechanical energy is sum of kinetic energy and gravitational potential energy:
E_i = K_i + U_i =  \frac{1}{2} m v_i^2 + (- \frac{GM}{r} )
where
m is the rocket's mass
v_i = 1.8 \cdot 10^4 m/s is the rocket initial speed
G=6.67 \cdot 10^{-11} m^3 kg^{-1} s^{-2} is the gravitational constant
M=5.97 \cdot 10^{24} kg is the Earth's mass
r= 6.37 \cdot 10^6 m is the distance of the rocket from the Earth's center (so, it corresponds to the Earth's radius)

The mechanical energy of the rocket when it is very far from the Earth is just kinetic energy (because the gravitational potential at infinite distance from Earth is taken to be zero):
E_f = K_f =  \frac{1}{2} mv_f ^2
where v_f is the final speed of the rocket.

By equalizing the initial energy and the final energy, we can find the final velocity:
\frac{1}{2} mv_i ^2 -  \frac{GM}{r} = \frac{1}{2}m v_f^2
v_f =  \sqrt{v_i^2 -  \frac{GM}{r} } =1.41 \cdot 10^4 m/s
3 0
3 years ago
Read 2 more answers
Course hero N4M.6 A board has one end wedged under a rock having a mass of 380 kg and is supported by another rock that touches
aleksandrvk [35]

Answer:

Therefore it is save to carry a 62kg adult

Explanation:

From the question we are told that:

Mass m=380kg

Height of supporting Rock X=85cm

Length of BoardL_r=4.5m

Mass of board M_b=22kg

Mass of adult M_a=62  

Generally the moment of balance about wedge part about  is mathematically given by

N -Q + R = Mg + mg

0.85*N - Mg*2.25 - mg*(2.25 + x) = 0

0.85*N  = + Mg*2.25 + mg*(2.25 + x)

where

N+R=4547

therefore

N = 570.70588 + 1608.3529 + 714.823 x

if N=0 at fallen person

x=3.04m

Therefore it is save to carry a 62kg adult

8 0
2 years ago
What is the difference between speed and velocity ?
gizmo_the_mogwai [7]
Speed is the distance traveled
                             time
but velocity is the change in distance
                                 time
7 0
2 years ago
Read 2 more answers
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