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Anna35 [415]
2 years ago
12

Can someone explain this to me please? I will give brainliest to the best answer!

Mathematics
2 answers:
mojhsa [17]2 years ago
8 0

The volume of a cylinder is V = \pi r^{2} h

  • r is the radius (half of the diameter which is 34m) --> 17m
  • height: 27m
  • \pi: 3.14

Thus the volume = \pi (17)^2*27=3.14*17^2*27=24501.42m^{3}

Hope that helped!

Debora [2.8K]2 years ago
7 0

Answer:

V = 24513.85 m³

Step-by-step explanation:

The Formula for the Volume of a Cylinder:

V = πr^{2}h

We know the diameter of the cylinder is 34 m.

To find the radius divide diameter by 2.

D = 2r

2r = 34m

r = 17m

The height is 27 m.

V = pi(17^{2})(27)

V = pi(289)(27)

Multiplying all of this gets you:

V = 24513.85 m³

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Five computer program modules are ranked as M1, M2, M3, M4, and M5 according to the ascending order of effort required to debug
gulaghasi [49]

Answer:

Follows are the solution to this question:

Step-by-step explanation:

Technician selects three out of 5 systems  

In C(5,3)=10ways, this can be achieved  

In part a:

Space sample chooses 3 of a 5 systems  

(M_1, \ M_2,\ M_3),(M_1,M_2,M_4) \ (M_1,M_2,M_5) \ (M_1,M_3,M_4) \ (M_1,M_3,M_5),(M_1,M_4,M_5) \ (M_2,M_3,M_4)\ (M_2,M_3,M_5) \ (M_2,M_4,M_5),(M_3,M_4,M_5)}

In point b:

A =MODULE WHICH INCLUDE M1 minimal amount of effort  

Outcomes probable =

(M_1,M_2,M_3),\ (M_1,M_2,M_4) \ (M_1,M_2,M_5)\ (M_1,M_3,M_4)\\\\(M_1,M_3,M_5),\ (M_1,M_4,M)5)\ =\ 6

\to p(A)=\frac{6}{10}\\\\

            =0.6

In point c:

B = highest effort that is M_5

Potential result=

(M_1,M_2,M_5) \ (M_1,M_3,M_5) \ (M_2,M_3,M_5)\(M_2,M_4,M_5) \\ (M_2,M_4,M_5), \ (M_3,M_4,M_5) \ =\ 6  \\\\

\to B= \frac{6}{10} \\\\

        =0.6

\to P(B)=10

In point d:

\to \ A  \ intersection \ B=(M_1,M_2,M_5), \ (M_1,M_3,M_5) \ ,(M_1,M_4,M_5)

\to A (A \ intersection \ B) = \frac{3}{10} \\\\\ \ \ \ \ \

                                      =0.3

In point e:

\to (A \cup B) =  (M_1,M_2,M_3),\ (M_1,M_2,M_4)\ (M_1,M_2,M_5)(M_1,M_3,M_4)\ (M_1,M_3,M_5), \\ (M_1,M_4,M_5)\ (M_2,M_3,M_5) \ (M_2,M_4,M_5),(M_3,M_4,M_5) \ = \ 9\to P(A \cap B)=\frac{9}{10}

                    = 0.9

In point f:

\to (A\cap B) = \frac{3}{10}

                 = 0.3

In point g:

\to (A \cup B) = \frac{7}{10}

                 =0.7

In point h:

\to p(A \cap B) = 0.3 \neq 0

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Step-by-step explanation:

Let's simplify step-by-step.

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Combine Like Terms:

=n+−4.6n+−3.3n+2.8n

=(n+−4.6n+−3.3n+2.8n)

=−4.1n

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Here, b is 6 so we have

\frac{2\pi}{ |6| }  =  \frac{\pi}{3}

So the period is pi/3, or 60 degrees

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