What is the quotient of (4x2 − 27x + 18) ÷ (x − 6)?

What value of n solves the equation 3n=1/81 N=___

Radda [10]

3n = 1/81; divide both sides by 3 to isolate n:

3n/3 = 1/81 divided by 3. Remember that when you divide, you use the reciprocal and multiply instead!!

n = 1/81(1/3) = 1/243. Now plug 1/243 back in for n, and 3/243 is equivalent to 1/81

7 0

3 years ago

6, -5 1/2, 0, -8/3, -0.79 from least to greatest

My name is Ann [436]

-5 1/2, -8/3, -0.79, 0, 6

6 0

3 years ago

True or false the order of magnitude for the number of tires on a motorcycle is 1

nlexa [21]

Answer:

false

Step-by-step explanation:

8 0

3 years ago

Suppose the value of a car depreciates 8% every year. To the nearest dollar, what will a car that cost $23,995 be worth after 5

Vanyuwa [196]

Answer:

The car will worth $15815 after 5 years.

Step-by-step explanation:

The formula is: $A=P(1+r)^t$ , where P = Initial cost, A = Final cost, r = Rate of change in cost per year and t = Number of years.

Here, $P= 23995, t= 5$

and $r= 8\%=0.08$

As here the value of the car depreciates every year, so we need to plug the value of $r$ as negative. So, $r=-0.08$

Now plugging the above values into the formula, we will get.....

$A=23995(1-0.08)^5\\ \\ A=23995(0.92)^5\\ \\ A=15814.6611... \approx 15815$

(Rounded to the nearest dollar)

So, the car will worth $15815 after 5 years.

8 0

3 years ago

An elementary school is offering 2 language classes: one in Spanish (S) and one in French (F). Given that P(S) = 50%, P(F) = 40%

nikklg [1K]

Answer:

(a) Probability that a randomly selected student is taking Spanish given that he or she is taking French = 0.5 .

(b) Probability that a randomly selected student is not taking French given that he or she is not taking Spanish = 0.6 .

Step-by-step explanation:

We are given that an elementary school is offering 2 language classes ;

Spanish Language is denoted by S and French language is denoted by F.

Also we are given, P(S) = 0.5 {Probability of students taking Spanish language}

P(F) = 0.4 {Probability of students taking French language}

$P(S\bigcup F)$ = 0.7 {Probability of students taking Spanish or French Language}

We know that, $P(A\bigcup B)$ = $P(A) + P(B) -$ $P(A\bigcap B)$

So, $P(S\bigcap F)$ = $P(S) + P(F) - P(S\bigcup F)$ = 0.5 + 0.4 - 0.7 = 0.2

$P(S\bigcap F)$ means Probability of students taking both Spanish and French Language.

Also, P(S)' = 1 - P(S) = 1 - 0.5 = 0.5

P(F)' = 1 - P(F) = 1 - 0.4 = 0.6

$P(S'\bigcap F')$ = 1 - $P(S\bigcup F)$ = 1 - 0.7 = 0.3

(a) Probability that a randomly selected student is taking Spanish given that he or she is taking French is given by P(S/F);

P(S/F) = $\frac{P(S\bigcap F)}{P(F)}$ = $\frac{0.2}{0.4}$ = 0.5

(b) Probability that a randomly selected student is not taking French given that he or she is not taking Spanish is given by P(F'/S');

P(F'/S') = $\frac{P(S'\bigcap F')}{P(S')}$ = $\frac{1- P(S\bigcup F)}{1-P(S)}$ = $\frac{0.3}{0.5}$ = 0.6 .

Note: 2. A pair of fair dice is rolled until a sum of either 5 or 7 appears ; This question is incomplete please provide with complete detail.

7 0

3 years ago