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defon
3 years ago
8

If two angles of a triangle are congruent then .. ? finish the sentence

Mathematics
1 answer:
miskamm [114]3 years ago
4 0
Theorem: If two<span> angles of a </span>triangle<span> are not </span>congruent<span>, </span>then<span> the </span>sides<span> opposite them are not </span>congruent<span>, and the longer </span>side<span> is opposite the larger angle. </span>Two<span> ways to prove that a </span>triangle<span> is isosceles </span>If<span> at least </span>two sides of a triangle are congruent,then<span> the </span>triangle<span> is isosceles</span>
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Which of the following functions is graphed below ? (:
Alekssandra [29.7K]
C is the answer.  By only looking at the domain (the stuff on the right in the functions), you can see that the first equation has a hole at x=2, meaning it does not have a value here at x=2.  When x<2, there are values for the 1st function.  When x>2, there are values for the second function, as well as when x=2
5 0
3 years ago
Danielle needs to walk 2.5 miles. If she wants to reach her destination in 30 minutes (1/2hour), how fast does she need to walk?
shepuryov [24]
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3 0
3 years ago
The sides of a triangle are x , x +1 , 2 x -1 and its area is x root of 10 .Find the value of x.
VARVARA [1.3K]


Ok, I'm going to start off saying there is probably an easier way of doing this that's right in front of my face, but I can't see it so I'm going to use Heron's formula, which is A=√[s(s-a)(s-b)(s-c)] where A is the area, s is the semiperimeter (half of the perimeter), and a, b, and c are the side lengths.

Substitute the known values into the formula:

x√10=√{[(x+x+1+2x-1)/2][({x+x+1+2x-1}/2)-x][({x+x+1+2x-1}/2)-(x+1)][({x+x+1+2x-1}/2)-(2x-1)]}

Simplify:

<span>x√10=√{[4x/2][(4x/2)-x][(4x/2)-(x+1)][(4x/2)-(2x-1)]}</span>

<span>x√10=√[2x(2x-x)(2x-x-1)(2x-2x+1)]</span>

<span>x√10=√[2x(x)(x-1)(1)]</span>

<span>x√10=√[2x²(x-1)]</span>

<span>x√10=√(2x³-2x²)</span>

<span>10x²=2x³-2x²</span>

<span>2x³-12x²=0</span>

<span>2x²(x-6)=0</span>

<span>2x²=0 or x-6=0</span>

<span>x=0 or x=6</span>

<span>Therefore, x=6 (you can't have a length of 0).</span>

6 0
3 years ago
Which of the following is the graph of y = negative StartRoot x EndRoot + 1? On a coordinate plane, an absolute value curve curv
mestny [16]

Answer:

  • B. On a coordinate plane, an absolute value curve curves up and to the right in quadrant 4 and starts at y = 1.

Step-by-step explanation:

<u>Graph of the function:</u>

  • y = -√x + 1

The domain is x ≥ 0, the range y ≤ 1

Correct answer choice is B

  • On a coordinate plane, an absolute value curve curves up and to the right in quadrant 4 and starts at y = 1.

<em>The graph is attached</em>

7 0
3 years ago
Read 2 more answers
Evaluate: <img src="https://tex.z-dn.net/?f=%5Csqrt%5B-3%5D%7B27%7D" id="TexFormula1" title="\sqrt[-3]{27}" alt="\sqrt[-3]{27}"
GenaCL600 [577]

Answer:

1/3 is the simplified form for given expression.

Step-by-step explanation:

Given that:

=\sqrt[-3]{27}

By simplifying:

Radical sign will be removed as follows:

= 27^{-1/3}

For removing the "-" sign from power, base will be inverted:

= (1/27) ^ {1/3}

27 can also be written as 3 * 3 * 3 = 3^3

So,

= (1/3^3)^{1/3}

= 1^{1/3} / 3^{3* 1/3}

By simplifying we get:

= 1/3

i hope it will help you!

6 0
3 years ago
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