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3 years ago

Solve the following simultaneous equation 2x+5y=16 and 10x-3y=-4

Mathematics

2 answers:

ss7ja [257]3 years ago

6 0

Answer:

Step-by-step explanation:

2x+5y=16 ......(1)

10x-3y=-4.......(2)

multiply (1) by -5

-10x-25y=-80 ......(1)

10x-3y=-4.......(2)

add (1) and (2)

-28y = -84

y = 3 put this value in (2) : 10x -9 = - 4

10x = 5

x = 1/2

mariarad [96]3 years ago

5 0

Answer:

( $\frac{1}{2}$ , 3)

Step-by-step explanation:

Given the 2 equations

2x + 5y = 16 → (1)

10x - 3y = - 4 → (2)

Multiplying (1) by - 5 and adding to (2) will eliminate the term in x

- 10x - 25y = - 80 → (3)

Add (2) and (3) term by term

(10x - 10x) + (- 3y - 25y) = (- 4- 80) ← simplify

- 28y = - 84 ( divide both sides by - 28 )

y = 3

Substitute y = 3 into (1) or (2) for corresponding value of x

(1) : 2x + 15 = 16 ( subtract 15 from both sides )

2x = 1 ( divide both sides by 2 )

x = $\frac{1}{2}$

Solution is ( $\frac{1}{2}$ , 3 )

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Express this is scientific notation

Vitek1552 [10]

Place the decimal point right after the first nonzero digit, which is 3.

So you'll go from this $0.003045$ to this $3.045$ after this move.

Now ask yourself: "how many spots must I move the decimal point to get back to 0.003045?"

The answer is "3 spots to the left"

The exponent of the final answer is -3
The negative indicates "move left" and the 3 tells us how many places to move the decimal

Therefore, $0.003045 = 3.045 \times 10^{-3}$

Answer: Choice C)
This is assuming you meant to write the -3 as an exponent

6 0

4 years ago

Thank you if you choose to help l

Aneli [31]

Answer:

xyz plz my answer as brainliest

3 0

4 years ago

Read 2 more answers

Number 1 and 2 please (25 points)

Elenna [48]

Answers:

1) $(3x+2)+(4-5x)=-2x+6$

$(3+2i)+(4-5i)=7-3i$

2) $(1-3x)(2+x)=-3x^{2}-5x+2$

$(1-3i)+(2+i)=5-5i$

Step-by-step explanation:

In mathematics there are rules related to complex numbers, specifically in the case of addition and multiplication:

Addition:

If we have two complex numbers written in their binomial form, the sum of both will be a complex number whose real part is the sum of the real parts and whose imaginary part is the sum of the imaginary parts (similarly as the sum of two binomials).

For example, the addition of these two binomials is:

$(3x+2)+(4-5x)=3x-5x+2+4=-2x+6$

Similarly, the addition of two complex numbers is:

$(3+2i)+(4-5i)=3+4+2i-5i=7-3i$ Here the complex part is the number with the $i$

Multiplication:

If we have two complex numbers written in their binomial form, the multiplication of both will be the same as the multiplication (product) of two binomials, taking into account that $i^{2}=-1$ .