Question

Solve the following simultaneous equation 2x+5y=16 and 10x-3y=-4​

Answer 1

Answer:

Step-by-step explanation:

2x+5y=16 ......(1)

10x-3y=-4​.......(2)

multiply (1) by -5

-10x-25y=-80 ......(1)

10x-3y=-4​.......(2)

add (1) and (2)

-28y = -84

y = 3 put this value in (2) : 10x -9 = - 4

10x = 5

x = 1/2

Answer 2

Answer:

($\frac{1}{2}$, 3)

Step-by-step explanation:

Given the 2 equations

2x + 5y = 16 → (1)

10x - 3y = - 4 → (2)

Multiplying (1) by - 5 and adding to (2) will eliminate the term in x

- 10x - 25y = - 80 → (3)

Add (2) and (3) term by term

(10x - 10x) + (- 3y - 25y) = (- 4- 80) ← simplify

- 28y = - 84 ( divide both sides by - 28 )

y = 3

Substitute y = 3 into (1) or (2) for corresponding value of x

(1) : 2x + 15 = 16 ( subtract 15 from both sides )

2x = 1 ( divide both sides by 2 )

x = $\frac{1}{2}$

Solution is ($\frac{1}{2}$, 3 )