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katen-ka-za [31]
3 years ago
10

It takes machine A x hours to manufacture a deck of cards that machine B can manufacture in y hours. If machine A operates alone

for z hours and is then joined by machine B until 100 decks are finished, for how long will the two machines operate simultaneously?
Mathematics
1 answer:
nlexa [21]3 years ago
3 0

Answer:

The expression that shows how long the two machines will operate simultaneously is:

\frac{y(100x-z)}{x+y}

Step-by-step explanation:

We know that:

x: hours to manufacture a deck of cards for machine A

y: hours to manufacture a deck of cards for machine B

z: hours that machine A operates alone

The number of decks manufactured only by machine A is:

\frac{z}{x}

So, the remaining decks are given by:

100-\frac{z}{x}=\frac{100x-z}{x}

Then, the combined rate of machines A and B would be:

\frac{1}{x} +\frac{1}{y} =\frac{x+y}{xy}

The work-rate formula is:

Amount= Rate \times Time

Hence, the time that the two machines work simultaneously is:

Time=\frac{Amount}{Rate}

Time=\frac{Amount}{Rate} =\frac{\frac{100x-z}{x} }{\frac{x+y}{xy} } ={\frac{100x-z}{x} \times \frac{xy}{x+y}=\frac{y(100x-z)}{x+y}

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