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7nadin3 [17]
3 years ago
15

CAN SOMEONE HELP ME? I NEED HELP ASAP PLZ!!!! TODAY!!!!! #4-#7

Chemistry
1 answer:
evablogger [386]3 years ago
4 0
4.it tells you that baking soda is an alkali
5. Because it it is very acidic it means it might not have very much water
6. Acid and more less then 7
7. It is different because it measures all different things where as the fahrenheit temperature only measures the temperature
Sorry about number 7 it isn't very good
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BRAINLIESIT IF CORRECT<br><br><br><br><br> 8
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I think ur answer would be refracted.

Explanation:

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Short Answer, Continued. Write short responses for each of the following questions. Limit text to less than 75 words. In some ca
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Answer:

I dont get it what am i supposed to do?

Explanation:

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List three ways in witch the water reaches the atmosphere
meriva
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Which evidence is an indication that a chemical reaction has occurred?
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6 0
3 years ago
To measure the amount of iron in a certain type of iron ore, an analytical chemist dissolves a sample in strong acid and titrate
Fiesta28 [93]

Answer:

\% Fe=11.4\%

Explanation:

Hello!

In this case, for the described chemical reaction, we find it is:

8H^+(aq)+5Fe^{2+}(aq)+MnO_4^-(aq)\rightarrow 5Fe^{3+}(aq)+Mn^{2+}(aq)+4H_2O(l)

Because it says that the iron is dissolved in a strong acid which provides addition hydrogen ions to the reaction media. Thus, for the questions attached on the figure we find:

- This a REDOX reaction because we see iron is being oxidized from 2+ to 3+ and manganese reduced from +7 to +2.

- Since it is a redox reaction and the oxidized species is that undergoing an oxidation number increase, we evidence iron goes from +2 to +3, which means iron is the oxidized species.

- In this case, for the used 59.2 mL (0.0592 L) of the 0.2000 M solution of potassium permanganate, we can compute the consumed grams of iron via stoichiometry including the 5:1 mole ratio between them in the chemical reaction:

m_{Fe^{2+}}=0.0592L*0.2000\frac{molMnO_4^-}{L}*\frac{5molFe^{2+}}{1molMnO_4^-}  *\frac{55.85gFe^{2+}}{1molFe^{2+}} \\\\m_{Fe^{2+}}=3.31gFe^{2+}

It means that the percent of iron in that sample is:

\% Fe=\frac{3.31g}{29.00g} *100\%\\\\\% Fe=11.4\%

Best regards.

5 0
3 years ago
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