All categories

3 years ago

4. How many moles of KBr are found in 3 Liters of 0.4 M solution?

Chemistry

1 answer:

Allisa [31]3 years ago

4 0

There are 1.2 moles of KBr found in 3 Liters of 0.4 M solution.

<h3>HOW TO CALCULATE NUMBER OF MOLES?</h3>

The number of moles of a substance can be calculated by multiplying the molarity by the volume.

No. of moles = Molarity × volume

According to this question, 3L of a KBr solution are contained in a 0.4M.

no. of moles = 3L × 0.4M = 1.2moles

Therefore, there are 1.2 moles of KBr found in 3 Liters of 0.4 M solution.

Learn more about no. of moles at: brainly.com/question/14919968

You might be interested in

What is the correct definition of a mixture?

jeka57 [31]

Answer:

a substance made by mixing other substances together.

Explanation:

A mixture is a substance made by mixing two or more substances together.

4 0

3 years ago

Read 2 more answers

Which property describes the way substances react with other substances to form new substances?

maxonik [38]

Answer:

Chemical Property describes the way substances react with other substances to form new substances.

Explanation:

Hope it helps you

3 0

3 years ago

Read 2 more answers

Which formula correctly represents the composition of iron III oxide

nikitadnepr [17]

The answer to the question is- Fe2O3

6 0

3 years ago

3. A thin lead apron is used to protect patients from harmful X rays. If the sheet measures 75.0 cm by 55.0 cm by 0.10 cm, and t

DanielleElmas [232]

Answer:

4.67 kg

Explanation:

Given data

Dimensions of the lead sheet: 75.0 cm by 55.0 cm by 0.10 cm

Density of lead: 11.3 g/cm³

Step 1: Calculate the volume of the sheet

The volume of the sheet is equal to the product of its dimensions.

$V = 75.0 cm \times 55.0 cm \times 0.10 cm = 413 cm^{3}$

Step 2: Calculate the mass of the sheet

The density (ρ) is equal to the mass divided by the volume.

$\rho = \frac{m}{V} \\m = \rho \times V = \frac{11.3g}{cm^{3} } \times 413cm^{3} = 4.67 \times 10^{3} g = 4.67 kg$

6 0

3 years ago

Consider the equation ∆G = –nFE, where F = 9.648533289 x 104 C/mol. Given that n is the mole of e– transferred and the following

myrzilka [38]

Answer:

See explanation below.

Explanation:

In the equation ∆G = –nFE, E is the electromotive force ( cell potential ) in Volts.

Now in turn a Volt is defined as the potential difference that will impart one joule of energy per coulomb of charge that moves through two points.

V = J/C where J is Joules and C is coulombs of charge

Therefore in terms of units the equation will give us units of Joules:

[ mol] x [C/mol] x [J/C] = [J]

5 0

3 years ago