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OleMash [197]
3 years ago
6

What is the best name for this molecule? Explain your naming process.

Chemistry
1 answer:
iogann1982 [59]3 years ago
7 0

Hi!


The best possible name for this molecule would be: 4 - ethyl - 1 - heptene or 4 - ethylhept - 1 - ene


We always name the molecule with respect to the longest chain (in a branched molecule), taking both atoms of carbon participating in the double bond into account too. In our case, this gives us a 7 Carbon chain - hept

ene - is the suffix that is indicative of the molecule being an alekene.

<em>So we know it is a branched heptene molecule</em>

We add the number where the double bond occurs either before ene, or before heptene as a rule.

<em>Note: We always start with the end of the chain from where the double bond is the closest, and number the carbons accordingly.</em>

The title and position of the branch always comes at the start. In our case the branch is a two carbon chain, and an alkane, so it would be an ethyl branch. This branch occurs at carbon number 4


Hence, the correct names would be:

<em>4 - ethyl - 1 - heptene</em> or <em>4 - ethylhept - 1 - ene</em>


Hope this helps!

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3 0
3 years ago
An enzyme with molecular weight of 310 kDa undergoes a change in shape when the substrate binds. This change can be characterize
oee [108]

Answer:

(a) r = 6.26 * 10⁻⁷cm

(b) r₂ = 6.05 * 10⁻⁷cm

Explanation:

Using the sedimentation coefficient formula;

s =  M(1-Vρ) / Nf ; where s is sedimentation coefficient, M is molecular weight, V is specific volume of protein, p is density of the solvent, N is Avogadro number, f if frictional force = 6πnr, n is viscosity of the medium, r is radius of particle

s = M ( 1 - Vρ) / N*6πnr

making r sbjct of formula, r =  M (1 - Vρ) / N*6πnrs

Note: S = 10⁻¹³ sec, 1 KDalton = 1 *10³ g/mol, I cP = 0.01 g/cm/s

r = {(3.1 * 10⁵ g/mol)(1 - (0.732 cm³/g)(1 g/cm³)} / { (6.02 * 10²³)(6π)(0.01 g/cm/s)(11.7 * 10⁻¹³ sec)

r = 6.26 * 10⁻⁷cm

b. Using the formula r₂/r₁ = s₁/s₂

s₂ = 0.035 + 1s₁ = 1.035s₁

making r₂ subject of formula; r₂ = (s₁ * r₁) / s₂ = (s₁ * r₁) / 1.035s₁

r₂ = 6.3 * 10⁻⁷cm / 1.035

r₂ = 6.05 * 10⁻⁷cm

8 0
3 years ago
Is the chemical equation CH4 +202 + 2H2O + CO2 balanced?
Soloha48 [4]

Answer:

I think C

Explanation:

because hydrogen on the right side only have two while on the left side it have 4

5 0
3 years ago
Read 2 more answers
10. pls pls help me
vagabundo [1.1K]

Answer:

2c2h2+502=4co2+H2O

Explanation:

this is the answer

8 0
3 years ago
SiCl4 + H2O = H4SiO4 + HCl
vichka [17]

Hey there!

Balance the equation:

SiCl₄ + H₂O → H₄SiO₄ + HCl

Balance H.

2 on the left, 5 on the right. Add a coefficient of 3 in front of H₂O and a coefficient of 2 in front of HCl.

SiCl₄ + 3H₂O → H₄SiO₄ + 2HCl  

Balance O.

3 on the left, 4 on the right. Change the coefficient of 3 in front of H₂O to a 4.

SiCl₄ + 4H₂O → H₄SiO₄ + 2HCl  

This unbalanced our H, so change the coefficient of 2 in front of HCl to a 4.

SiCl₄ + 4H₂O → H₄SiO₄ + 4HCl  

Balance Cl.

4 on the left, 4 on the right. Already balanced.

Balance Si.

1 on the left, 1 on the right. Already balanced.

Our final balanced equation:

SiCl₄ + 4H₂O → H₄SiO₄ + 4HCl

Hope this helps!

8 0
3 years ago
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