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Fynjy0 [20]
3 years ago
13

Determine the molecular geometry based on the description of bonding and lone pairs of electrons around the central atom. Three

double bonds and no lone pairs of electrons Choose... Two single bonds and two lone pairs of electrons Choose... Five single bonds and no lone pairs of electrons Choose... Three single bonds and one lone pair of electrons Choose... Two double bonds and no lone pairs of electrons Choose... Four single bonds and no lone pairs of electrons Choose... Six single bonds and no lone pairs of electrons Choose...
Chemistry
1 answer:
Inessa05 [86]3 years ago
5 0

Answer:

Three double bonds and no lone pairs of electrons- trigonal planar

Two single bonds and two lone pairs of electrons-bent

Five single bonds and no lone pairs of electrons- trigonal bipyramidal

Three single bonds and one lone pair of electrons- trigonal pyramidal

Two double bonds and no lone pairs of electrons - linear

Four single bonds and no lone pairs of electrons- tetrahedral

Six single bonds and no lone pairs of electrons- octahedral

Explanation:

The valence shell electron pair repulsion theory gives a description of the shape of a molecule based on the number of regions of electron density present on the valence shell of the central atom of the molecule.

The molecules are distorted away from the shape predicted on the basis of the VSEPR by the presence of lone pairs on the valence shell of the central atom in the molecule. In the absence of lone pairs, the shape of a molecule is exactly the shape predicted on the basis of the VSEPR theory.

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Typical "hard" water contains about 2.0 x 10–3 mol of Ca2+ per liter. Calculate the maximum concentration of fluoride ion that c
malfutka [58]

Answer:

[F^-]_{max}=4x10{-3}\frac{molF^-}{L}

Explanation:

Hello,

In this case, for the described situation, we infer that calcium reacts with fluoride ions to yield insoluble calcium fluoride as shown below:

Ca^{+2}(aq)+2F^-(aq)\rightleftharpoons CaF_2(s)

Which is typically an equilibrium reaction, since calcium fluoride is able to come back to the ions. In such a way, since the maximum amount is computed via stoichiometry, we can see a 1:2 mole ratio between the ions, therefore, the required maximum amount of fluoride ions in the "hard" water (assuming no other ions) turns out:

[F^-]_{max}=2.0x10^{-3}\frac{molCa^{2+}}{L}*\frac{2molF^-}{1molCa^{2+}}  \\

[F^-]_{max}=4x10{-3}\frac{molF^-}{L}

Best regards.

8 0
2 years ago
What is energy in motion called
oee [108]
Is it kinetic energy
3 0
3 years ago
A) 30.22 g NaCl x 1 mol NaC l =      58.4430 Molar mass (g) NaCl=0.5171 mol NaCl
jekas [21]
The third question requires you to solve for the weight of sodium (Na) and weight of Chloride (Cl) from the calculated moles of each element Na, and Cl.

So, you need to multiply the calculated moles of Na with its molar mass (23 g/ mol) to get the answer for Na. And multiply the calculated moles of Cl with its molar mass (35.45 g/mol) to get the answer for Cl. 
6 0
3 years ago
A gas within a piston–cylinder assembly undergoes an isothermal process at 400 K during which the change in entropy is −0.3 kJ/K
Karolina [17]

Answer:

W = -120 KJ

Explanation:

Since the piston–cylinder assembly undergoes an isothermal process, then the temperature is constant.

Thus; T1 = T2 = 400K

change in entropy; ΔS = −0.3 kJ/K

Formula for change in entropy is written as;

ΔS = Q/T

Where Q is amount of heat transferred.

Thus;

Q = ΔS × T

Q = -0.3 × 400

Q = -120 KJ

From the first law of thermodynamics, we can find the workdone from;

Q = ΔU + W

Where;

ΔU is Change in the internal energy

W = Work done

Now, since it's an ideal gas model, the change in internal energy is expressed as;

ΔU = m•C_v•ΔT

Where;

m is mass

C_v is heat capacity at constant volume

ΔT is change in temperature

Now, since it's an isothermal process where temperature is constant, then;

ΔT = T2 - T1 = 0

Thus;

ΔU = m•C_v•ΔT = 0

ΔU = 0

From earlier;

Q = ΔU + W

Thus;

-120 = 0+ W

W = -120 KJ

8 0
3 years ago
What is the Chemical Formula and Net Ionic Equations for all three solutions.
AlladinOne [14]

Answer:

See answer below

Explanation:

As you are asking for chemical formula and ionic equation, then, I will assume that after the station #3 below, are the solutions you are requiring.

You are also not specifing if you want for example, result of solution 1 + solution 3. If you need that, please post that on another question.

Now for the chemical formula, you need to identify the elements in all 3 solutions, and also the type of compound.

<u>1. Solution 2 Potassium Iodide: </u>

In this case we have Potassium on one side, and Iodine on the other side, the symbol for those are K and l. As Potassium have the +1 oxidation state, cause is the only one that it can have, when it's next to an halide like chlorine or bromine, it will form a binary salt. The halides, usually work with the lowest oxydation state. In the case of Iodide it will be -1, so, the formula will be:

KI

And the net ionic equation will be the chemical equation that shows how the charges and atoms are balanced. In this case it would be:  

K⁺ + I⁻ ------> KI

<u>2. Solution 1 and 3, Lead (II) nitrate and Sodium carbonate: </u>

In this case I will work with both, because both of the solution are tertiary compounds. In this cases, we have two tertiary salt, The Sodium symbol is Na, and is working with it oxydation state +1. Carbonate is an anion and have the formula CO₃ working with the oxydation state -2. Lead can work with oxidation state +2 and +4. It's symbol is Pb. Nitrate is NO₃ and works with oxydation state -1 instead.

The chemical formula and ionic equation for both will be:

Lead(II) nitrate: Pb(NO₃)₂

Sodium Carbonate: Na₂CO₃

And the net equations:

Lead nitrate: Pb²⁺ + 2NO₃⁻ ------> Pb(NO₃)₂

Copper sulfate: 2Na⁺ + CO₃²⁻ -------> Na₂CO₃

Hope this helps

6 0
2 years ago
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