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2 years ago

What the study of Molecules?

Chemistry

1 answer:

dangina [55]2 years ago

7 0

The study of molecules is referred to as molecular biology.

A molecule refer to a group of two (2) or more atoms that are chemically bonded together, so as to form the smallest fundamental unit of a chemical compound. Also, molecules are capable of taking part in a chemical reaction.

In Science, molecular biology can be defined as a branch of biology that is mainly focused on the study of molecules, especially the processes and chemical structure that are associated with biological concepts and phenomena such as:

Cells

Photosynthesis

Organs

Tissues

Respiration

Muscles

In conclusion, the study of molecules is referred to as molecular biology.

Read more on molecular biology here: brainly.com/question/368331

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What kind of radioactive element is useful for dating an object?

OlgaM077 [116]

The kind of radioactive element is useful for dating an object is one with a half-life close to the age of the object.

<h3>What are radioactive elements?</h3>

Radioactive elements are elements that involved in radioactivity and this comprises of atoms or particles in their nuclei whose atomic nuclei are not stable and they emit radiations to maintain stability.

Therefore, The kind of radioactive element is useful for dating an object is one with a half-life close to the age of the object.

Learn more about radioactive elements below.

brainly.com/question/10257016

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4 0

2 years ago

Determine the enthalpy change for the decomposition of calcium carbonate. CaCO₃(s) --> CaO(s) + CO₂(g) given the thermochemic

Hunter-Best [27]

Answer: c. 179 kJ/mol

Explanation:

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to Hess’s law, the chemical equation can be treated as algebraic expressions and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

Given:

$Ca(OH)_2(s)\rightarrow CaO(s)+H_2O (l)$ $\Delta H_1= 65.2 kJ/mol$ (1)

$Ca(OH)_2(s)+CO_2(g)\rightarrow CaCO_3(s)+H_2O(l)$ $\Delta H_2= -113.8 kJ/mol$ (2)

$C(s)+O_2(g)\rightarrow CO_2(g)$ $\Delta H_3= -393.5 kJ/mol$ (3)

$2Ca(s)+O_2(g)\rightarrow 2CaO(s)$ $\Delta H_4=-1270.2 kJ/mol$ (4)

On subtracting eq (1) from eq (2) we have:

$Ca(OH)_2(s)\rightarrow CaO(s)+H_2O(l)$ - $Ca(OH)_2(s)+CO_2(g)\rightarrow CaCO_3(s)+H_2O(l)$

$CaCO_3(s)\rightarrow CaO(s)+CO_2(g)$

$\Delta H=-113.8-(65.2)kJ/mol=-179kJ/mol$

Hence the enthalpy change for the raection is 179.0 kJ/mol.

6 0

3 years ago

What is the density of CHCL3 vapor at 1.00atm and 298K?

Advocard [28]

Answer:

4.8 g/mL is the density of chloroform vapor at 1.00 atm and 298 K.

Explanation:

By ideal gas equation:

$PV=nRT$

Number of moles (n)

can be written as: $n=\frac{m}{M}$

where, m = given mass

M = molar mass

$PV=\frac{m}{M}RT\\\\PM=\frac{m}{V}RT$

where,

$\frac{m}{V}=d$ which is known as density of the gas

The relation becomes:

$PM=dRT$ .....(1)

We are given:

M = molar mass of chloroform= 119.5 g/mol

R = Gas constant = $0.0821\text{ L atm }mol^{-1}K^{-1}$

T = temperature of the gas = $298K$

P = pressure of the gas = 1.00 atm

Putting values in equation 1, we get:

$1.00atm\times 119.5g/mol=d\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 298K\\\\d=4.88g/L$

4.8 g/mL is the density of chloroform vapor at 1.00 atm and 298 K.

7 0

3 years ago

Does adding salt to water lower its freezing point science project

ser-zykov [4K]

Yes, it does. The freezing point of the salt solution is lower than the freezing point of pure water since there will be more particles, which are water molecules plus salt molecules, present in the salt solution. The salt molecules will slow down the amount of crystals formed resulting to a lower freezing point.

8 0

4 years ago

Our good friend and pseudo scientist, homer simpson, attempts to analyze 300 mg of an unknown compound containing only c and h b

iragen [17]

$C_{x}H_{y} + O_{2} --\ \textgreater \ x CO_{2} + \frac{y}{2} H{2}O

540mg H_{2}O* \frac{1 mmol H_{2}O}{18 mg H_{2}O} =30 mmol H_{2}O

\\ \\30 mmolH_{2}O -have - 60 mmol H
\\ \\ 60 mmol H* \frac{1mg H}{1 mmol H} =60 mg H
\\ \\300mg C_{x}H_{y} - 60 mg H= 240 mg C
\\ \\ 240 mgC* \frac{1mmol}{12mg} =20 mmol C

20 mmol C: 60 mmol H=1 mol C : 3 mol H

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7 0

4 years ago

What the study of Molecules?​

What the study of Molecules?