The molarity of the solution of H₃PO₄ needed to neutralize the KOH solution is 0.35 M
<h3>Balanced equation </h3>
H₃PO₄ + 3KOH —> K₃PO₄ + 3H₂O
From the balanced equation above,
- The mole ratio of the acid, H₃PO₄ (nA) = 1
- The mole ratio of the base, KOH (nB) = 3
<h3>How to determine the molarity of H₃PO₄ </h3>
- Volume of acid, H₃PO₄ (Va) = 10.2 mL
- Molarity of base, Ca(OH)₂ (Mb) = 0.2 M
- Volume of base, Ca(OH)₂ (Vb) = 53.5 mL
- Molarity of acid, H₃PO₄ (Ma) =?
MaVa / MbVb = nA / nB
(Ma × 10.2) / (0.2 × 53.5) = 1 / 3
(Ma × 10.2) / 10.7 = 1 / 3
Cross multiply
Ma × 10.2 × 3 = 10.7
Ma × 30.6 = 10.7
Divide both side by 30.6
Ma = 10.7 / 30.6
Ma = 0.35 M
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Answer:
C
Explanation:
It said in water it had a freezing point of 0.352oC. so right i the start i picked C because it sounds like it doesn't dissociates in water so that is my answer
- Hope this helps
- This is my answer
- Ask any questions if wrong plz and thank you
Answer:
See details below
Explanation:
The balanced reaction equation is given below:
+ 
→ 
+ 
Mole fraction of CO2 to H20
= 8/10 = 
Mole ratio of C4H10 to CO2 is 2:8 = 1:4
1 mole of n-butane - 38.12 g
4 moles - ?
= 152.48g fuel consumed.
Answer:
uhhh i do not know this but we are learning at my school i could give you the answer soon i you want
Explanation:
