First calculate the moles of N2 and H2 reacted.
moles N2 = 27.7 g / (28 g/mol) = 0.9893 mol
moles H2 = 4.45 g / (2 g/mol) = 2.225 mol
We can see that N2 is the limiting reactant, therefore we
base our calculation from that.
Calculating for mass of N2H4 formed:
mass N2H4 = 0.9893 mol N2 * (1 mole N2H4 / 1 mole N2) * 32
g / mol * 0.775
<span>mass N2H4 = 24.53 grams</span>
Solution :
Term Best description
Eriochrome Black T EBT
Starting color, before titration Pale purple-pink color
Molecule that has a high affinity for metal ions Chelating agent
Ethylenediaminetetracetic acid EDTA
Color at the completion of titration Blue-gray color
Bronze is alloy mixture of copper and tin.
Answer:
Boyle's Law, Charles' Law, and Gay-Lussac's Law
Explanation: