Answer:
Caused by gravity and the roller coaster's position, the potential energy is stored in the roller coaster. For example, this ball is at the top of a hill, where potential energy is at it's highest.
Explanation:
<span>Ball A with a mass of 0.500 kg is moving east at a velocity of 0.800 m/s. It strikes ball B, also of mass 0.500 kg, which is stationary. Ball A glances off B at an angle of 40.0° north of its...Two smart cars depart from the same starting location at the same time and travel different routes to the same destination, arriving at the same time. Explain why the cars travelled different...Given electric flux density D=0.3r^2 ar nc/m^2 in free space a. Find the total charge within the sphere r=3 b. Find the total electric flux leaving the sphere r=4</span>
Answer: A cold front occurs when a cold air mass advances into a region occupied by a warm air mass. If the boundary between the cold and warm air masses doesn't move, it is called a stationary front.
Explanation: Two types of occluded front exist: the warm-type and the cold-type. They’re distinguished by the relative temperatures of the air mass ahead of the occlusion – in other words, the air mass ahead of the original warm front – and the air mass behind the cold front. If the air behind the cold front is colder than the air ahead of the occlusion, it shoves beneath that air (because it’s denser) to form a cold-type occluded front. If the air behind the cold front is warmer than the air ahead, it rides over it to form a warm-type occluded front – which appears to be the more common case. In either situation, the lighter warm air representing the air mass originally between the warm and cold fronts sits above the boundary between the two cooler air masses.
Hope this helps!!
<span>A light-year is the total distance that light can travel in 1 year.
Since, We know the speed of light (c) in vacuum= 299792458 metres per second
And, there are 365.25 days in an year, or t= (365.25*24*60*60) seconds
Hence a light-year (d)=c*t
=299792458Ă—365.25Ă—24Ă—60Ă—60 metres
=9,460,730,472,580,800 metres
â‰9.46073Ă—10^15 metres</span>
The weight of an object is given by:
where
F is the weight
m is the mass of the object
is the gravitational acceleration
The piece of ham in this problem has a mass of
m=630 g = 0.63 kg
therefore its weight is
